119 (atomic mass)- 50 protons= 69 neutrons
Answer:
0.0023 cm
Explanation:
The following data were obtained from the question:
Length (L) = 55 cm
Breadth (B) = 23.3 cm
Volume (V) = 2.9 cm³
Thickness (T) =?
Thus, we can obtain the thickness of the aluminum foil as illustrated below:
V = L × B × T
2.9 = 55 × 23.3 × T
2.9 = 1281.5 × T
Divide both side by 1281.5
T = 2.9/1281.5
T = 0.0023 cm
Therefore, the thickness of the aluminum foil is 0.0023 cm
Answer:
2.02 g H₂
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
Explanation:
<u>Step 1: Define</u>
22.4 L H₂ at STP
<u>Step 2: Identify Conversions</u>
STP - 22.4 L / mol
Molar Mass of H - 1.01 g/mol
Molar Mass of H₂ - 2(1.01) = 2.02 g/mol
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<u>Step 3: Convert</u>
<u />
= 2.02 g H₂
The particles slow down and the attractive forces between particles increase.