Answer:
2.19L
Explanation:
Information from the question include:
V1 (initial volume) = 2.3L
P1 (initial pressure) = 725mmHg
P2 (final pressure) = 760mmHg
V2 (final volume) =?
With the Boyle's law equation P1V1 = P2V2, the final volume can easily be obtain as follow:
P1V1 = P2V2
725 x 2.3 = 760 x V2
Divide both side by 760
V2 = (725 x 2.3)/760
V2 = 2.19L
Therefore, the new volume of the gas at standard pressure is 2.19L
Answer:atoms involved in reaction. Mass remains same in reaction
Explanation: hug would be fine!
The correct answer is 3) 2CO2(g) ⇄ 2CO(g) + O2(g)
this is the correct one because it is a decomposition reaction and all the number of atoms is equal on both sides.
there are 2 C atoms on both sides.
and 4 O atoms on both sides.
and 1) the atoms numbers are equal on both sides but not correct as it not a
correct number as it has 1/2 O2.
and 2) CO2(g) ⇆ CO(g) + O2
the number of O atoms is not equal on both sides of the equation.
we have 2 O atoms on the left side and 3 O atoms on the right side.
so, this not a balanced equation.
4) also not correct 2CO(g) + O2 ⇆ 2CO2
as it is not a decomposition reaction and the 2CO & O2 are as reactants not products.
so the correct answer is 3) 2CO2(g) ⇆ 2CO(g) + O2(g)
I think that the answer is (D)... I hope this helped
