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puteri [66]
3 years ago
15

The end point in a titration of a 58mL sample of aqueous HCl was reached by the addition of 25mL of 0.83MNaOH titrant. The react

ion proceeds by the following equation. HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l) What is the molar concentration of HCl?
Chemistry
1 answer:
Bess [88]3 years ago
4 0

Answer:

0.36 M

Explanation:

Let's consider the following neutralization reaction.

HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

25 mL of 0.83 M NaOH reacted. The moles of NaOH that reacted are:

0.025 L × 0.83 mol/L =0.021 mol

The molar ratio of NaOH to HCl is 1:1. The moles of HCl that reacted are 0.021 moles.

0.021 moles are contained in 58 mL of HCl. The molar concentration of HCl is:

M = 0.021 mol/0.058 L

M = 0.36 M

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a thin solid glass rod that is used in chemistry to combine substances. A stirring rod often has rounded ends and is about the length of a long straw.

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A crucial component of lab apparatus for mixing chemicals and liquids for reactions is a long, thin stirring rod. Stirring rods are made of solid plastic, glass, or steel and are non-abrasive, chemically inert, and chemically resistant.

<h3>What is the name of the glass stirring rod?</h3>

Glass rod, also known as a stirring rod, stir rod, or solid glass rod, is frequently made of quartz and borosilicate glass. Its diameter and length can be modified to meet your needs.

<h3>Does filtration employ stirring rods?</h3>

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2 years ago
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3 years ago
If a reaction occurs, what will be the products of the unbalanced reaction below?Zn(s) + HCl(aq) --&gt;
irakobra [83]

The products will be ZnCl_2(s) + H_2(g)

<h3>Chemical reactions</h3>

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The equation of the reaction becomes: Zn(s) + HCl(aq) -- > ZnCl_2 (s) + H_2 (g)

Hydrogen gas is released as a result. In fact, it is one of the ways of preparing hydrogen gas in the laboratory.

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3 0
2 years ago
Calculate the number of moles of iodine in 7.68×10^25 molecules of I2
Dmitrij [34]

Answer:

<h2>127.57 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{7.68 \times  {10}^{25} }{6.02 \times  {10}^{23} }   \\  = 127.574750...

We have the final answer as

<h3>127.57 moles</h3>

Hope this helps you

4 0
3 years ago
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