Answer:
The correct answer is Option C (E1) and Option B (carbocation).
Explanation:
- Intramolecular immunity idols are considered as that of the formation mechanism with E1 responses or reactivity.
- Reactants with E1 were indeed obligations of both parties, meaning that an E1 reaction was conducted thru all the two stages known as ionization but rather deprotonation. Involves the absence of either an aromatic ring, a carbocation has been generated throughout the ionization solution.
Some other possibilities offered aren't relevant to the procedure outlined. So the above alternative is accurate.
Answer:
LiOH (aq) + VCl3(aq) ---> LiCl(aq) + V(OH)3(s) - unbalanced
3LiOH (aq) + VCl3(aq) ---> 3LiCl(aq) + V(OH)3(s) - balanced
3Li+OH- (aq) + V3+(Cl-)3(aq) ---> 3Li+Cl-(aq) + V3+(OH-)3(s) - showing ions
3Li+(aq) + 3OH- (aq) + V3+(aq) + 3Cl-(aq) ---> 3Li+(aq) + 3Cl-(aq) + V3+(OH-)3(s) (some courses don't show the charges in insoluble ionic compounds - so V(OH)3(s)) - Showing soluble ionic compounds as separate ions.
3OH- (aq) + V3+(aq) ---> V3+(OH-)3(s) (or V(OH)3(s)) - without spectator ions
Explanation:
i don't know if this is right ore not but i hope this helps even if it is just a little bit sorry if this does not help i truly apologize
Answer:
false
in chemical reaction element doesnot change into another
Explanation:
Answer:
a) 12/323
b) 8/233
Explanation:
a) The probability of a red ball being drawn is 12/38, or in a simplified fraction, 6/19. To find the probability that 3 are red you would multiply the probability of the fraction for each, except subtracting one from the total each time as the drawn is done without replacement. This is done as follows: 6/19 × 6/18 × 6/17= 12/323
b) The probability of drawing a blue ball is 8/38, or 4/19. To find that the first one is blue and the rest are red, the equation is done as follows: 4/19 × 6/18 × 6/17 = 8/233
(hopefully I did this right)
Answer:
B.) As a medium star
Explanation:
A.) is incorrect. It is not a giant star because there a millions are stars which are much more massive.
B.) is correct. Our Sun has a radius of about 437,000 miles. Technically our Sun is classified as a G-type main-sequence star, aka. yellow dwarf star. The Sun is generally classified as this type of star.
C.) is incorrect. While the Sun's light is similar to the light of white dwarf, it is still most certainly classified as a yellow dwarf star.
D.) is incorrect. Neutrons stars are collapsed, incredibly dense stars. They are around the size of a city.
