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11Alexandr11 [23.1K]
3 years ago
7

Nathan ended round one of a quiz with 200 points. In round

Mathematics
1 answer:
pochemuha3 years ago
3 0

Answer:

100 points

Step-by-step explanation:

maths and more maths

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What is the probability of tossing a coin three times and getting tails each time?
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Answer:

1/8

Step-by-step explanation:

This is a compund probability problem. You need to find the probability of each event and then multiply the probabilities together.

The probability of flipping tails is 1/2. We need three of these.

1/2 x 1/2 x 1/2 = 1/8

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Plis necesito ayuda en esta tarea:
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8. What are the advantages of switching a quadratic function from standard form into vertex form?
Airida [17]

Answer:

vertex form automatically gives you your vertex and your y intercept so all you need to do is graph. Hope this helps

Step-by-step explanation:

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3 years ago
What would the bottles purchased be and what would the bottles recycled be?
N76 [4]

Part A

Your problem statement already shows you the conversion.

Bottles purchased: 5×10¹⁰

Bottles recycled: 8.3×10⁹

Part B

The ratio of bottles purchased to bottles recycled is

... (5×10¹⁰)/(8.3×10⁹) = 0.6×10¹ = 6.0

The number of bottles purchased is 6 times the number of bottles recycle.

5 0
3 years ago
Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]
Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

  • f(x) = \frac{3x-2}{x+1}
  • g(x)=x+5
  • f[ -4 ] = ?
  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0
2 years ago
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