d = dimes
q = quarters
d+q = 38 coins
q=38-d
0.25q + 0.10d=6.95
0.25(38-d)+0.10d=6.95
9.5-0.25d+0.10d=6.95
-015d=-2.55
d=-2.55/-0.15 = 17
q=38-17 =21
21*0.25 =5.25
17*0.10 = 1.70
5.25+1.70 = 6.95
she had 21 quarters and 17 dimes
Answer:
n+18=7(n-3)
Step-by-step explanation:
Lets replace "A number" with the variable n because we do not know its value!
1) Rewrite the problem as an equation
n+18=7(n-3)
<u>If we want to solve the equation, do the following:</u>
1) Distribute 7 to n and -3:
n+18=7n-21
2) Add 21 to both sides:
n+39=7n
3) Subtract n from both sides:
39=6n
4) Divide both sides by 6:
n=6.5
Look at where the line crosses the X axis.
Here we see it crosses -2
So your answer is A (-2, 0)
