Answer:
there are 10 viable bacterial cells in 1 ml in the 1/100 dilution tube
Explanation:
in 1ml there is 1000 viable bacterial cells → diluted with 9 ml of solvent (10 ml in total)→ 1000 viable bacterial cells in 10 ml (fist tube)
now we take 1 ml of the first tube into the second empty tube → has 1000/10 = 100 viable bacterial cells on 1 ml → diluted with 9 ml of solvent (10 ml in total)→ 100 viable bacterial cells in 10 ml (second tube)
then we take 1 ml of the second tube into the third empty tube → has 100/10 = 10 viable bacterial cells in 1 ml → diluted with 9 ml of solvent (10 ml in total)→ 10 viable bacterial cells in 10 ml (third tube)
therefore there are 10 viable bacterial cells in 1 ml in the 1/100 dilution tube
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