How many square feet of outdoor carpet will we need for this whole?

Mathematics

2 answers:

Black_prince [1.1K]2 years ago

7 0

1/2((6)(3)). (6)(12). 72-9
1/2(18). 72. 63ft squared
9

Dmitrij [34]2 years ago

3 0

Answer:

Step-by-step explanation:

The green part, I take is what is already covered, not what has to be covered.

The triangle is what you need to find which is given as 9 square feet. So the first statement can't be right.

Here you have to subtract 9 from 72

Area needed = 72 - 9 = 63 square feet.

72 square feet would be the amount with the triangle filled in.

63 square feet is the number of square feet needed with the triangle cut out.

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Evaluate this expression. y + 7, if y = 12

photoshop1234 [79]

Answer:

$\huge{ \boxed{ \sf{19}}}$

Step-by-step explanation:

$\underline{ \sf{Given}} : \sf{y = 12}$

$\underline{ \sf{To \: Find}} : \sf{Value \: of \: the \: given \: expression}$

$\sf{y + 7}$

plug the value of y

$\mapsto{ \sf{12 + 7}}$

Add the numbers: 12 and 7

$\mapsto{ \sf{19}}$

Hope I helped!

Best regards! :D

~ $\text{TheAnimeGirl}$

6 0

2 years ago

Read 2 more answers

Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x. (10 points)

USPshnik [31]

See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
$M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) + f(\frac{x_{1} + x_{2} }{2}) + ... + f(\frac{x_{n-1} + x_{n} }{2})]$

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
$M_{4} = \frac{1 - 0}{4} [ f(\frac{0 + \frac{1}{4} }{2}) + f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) + f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]$
$M_{4} = \frac{1}{4} [ f(\frac{1}{8}) + f(\frac{3}{8}) + f(\frac{5}{8}) + f(\frac{7}{8})]$

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
$M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]$

$M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]$

M₄ = 1/4 · (2 - 478/512)
= 0.2666

Hence, the area of the region bounded by y = x³ and y = x is approximately 0.267 square units.