N=(x)+M+(B) that's ur answer
So here is how you solve for the answer.
Firstly, you solve for the Area of Rectangle A.
The formula for Area is Length x width.
So A = (2x + 6)(3x) and the result is: 6x^2 + 18x
Now, let y be the width of rectangle B.
<span>(x+2) (y) = 6x^2 + 18x + 12
(x+2) y = 6(x+1)(x+2)
y = 6(x+1)
</span>So the final answer would be width is 6x + 6. The answer is the third option. Hope this answer helps.
It's 33 because If you divide it by 8 equal groups, you get 4 in each group and 1 left over. 4 is also an even number! Good luck
Do you have a multiple choice selection of answers, because there is no way to pick a job out of the blue without certain choices and a math problem set up.
Answer: C. Two of the side lengths add to a sum that is less than the third side length, so these lengths cannot be used to draw any triangles.
Explanation:
Those two sides in question are 8 and 12. They add to 8+12 = 20, but this sum is less than the third side 24. A triangle cannot be formed.
Try it out yourself. Cut out slips of paper that are 8 units, 12 units, and 24 units respectively. The units could be in inches or cm or mm based on your preference.
Then try to form a triangle with those side lengths. You'll find that it's not possible. If we had the 24 unit side be the horizontal base, so to speak, then we could attach the 8 and 12 unit lengths on either side of this horizontal piece. But then no matter how we rotate those smaller sides, they won't meet up to form the third point for the triangle. The sides are simply too short. Other possible configurations won't work either.
As a rule, the sum of any two sides of a triangle must be larger than the third side. This is the triangle inequality theorem.
That theorem says that the following three inequalities must all be true for a triangle to be possible.
where x,y,z are the sides of the triangle. They are placeholders for positive real numbers.
So because 8+12 > 24 is a false statement, this means that a triangle is not possible for these given side lengths. Therefore, 0 triangles can be formed.
