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3 years ago

HELPPPPPPPPPPPPPPP PLEASEEEEEEEEEEEEE!!!!!!!!!!!11

Mathematics

1 answer:

mr_godi [17]3 years ago

7 0

To find the perimeter, the equation is (w2 + l2 = p)

Where w is width and l is length and p is perimeter.

If you have the width, then you double it for both widths.

Then subtract that number from the perimeter.

150-60 = 90

90 is the remaining number for the lengths. Since both lengths needs to be equal, you split the 90. 45.

You length equals 45.

45(2) + 30(2) = Perimeter of 150.

Your answer is 45.

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Janet is designing a frame for a client. She wants to prove to her client that m∠AGE ≅ m∠CHE in her sketch. What is the missing

Amiraneli [1.4K]

Answer:

I believe the answer is transative property. I'm currently taking the test so I'm not 100% sure if I'm right yet.

Step-by-step explanation:

In step one, AGE and HGB are verticle angles since they are opposite of each other. then step two is alternate interior angles because they are interior angles opposite of each other, self-explanatory. the reason I choose the transitive property over the corresponding angles theorem is because the transitive property states: among A B and C, if A=B and B=c then A=C and in this case since AGE=HGB andHGB=CHE then AGE=CHE. I hope this helps and if you know the right answer just put it in the comments, if I'm wrong ofc.

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natali 33 [55]

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An aeroplane takes 4 hours to travel a distance of 440 0km. Another aeroplane travels at a speed which is 100km per hour less th

FrozenT [24]

Answer:

7480 hours

Step-by-step explanation:

440 - 100 = 340

LCM of 440 and 340

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LCM = 2 × 2 × 2 × 5 × 11 × 17

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3 years ago

Write the expression of the quotient of 44 and 11

VladimirAG [237]

Answer:

Step-by-step explanation:

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3 years ago

The graph of f(x)=ax^2 is narrower than the graph of g(x)=dx^2 when a<d

Lynna [10]

Answer:

Step-by-step explanation:

as given in question that a > 0 so

if we put a=1

we get g(x) = f(x)

now put a =2

we get

g(x) = 2 f(x)

here we can see that g(x) would always be greater than or equals to f(x)

so we can say that the graph of g(x) will never be narrower than graph of g(x)

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