Answer:
12 x is the answer. please thanks and follow me.
Refer to the figure given below while reading the solution.
Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.
And then position B when traveled 5 m towards the right turning 90°.
We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).
Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).
Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.
- The shortest distance of B from PQ = AC-AD
- The shortest distance of B from SR = 44-(AC-AD)
- The shortest distance of B from SP = AC+AD
- The shortest distance of B from RQ = 44-(AC+AD)
So, the average of the shortest distances of B from each side is
Hence, the average of the shortest distance of B from each side is 22 m
Learn more about average here-
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Symmetric property, I remembered the answer for this for my summer school. This is one of the equivalence properties of equality.
Answer:
60?
Step-by-step explanation:
Answer:
The equation you are asking for is
40*(t+3) = 55*t,
where t is the time counted after the second car started.
The equation says that the distance covered by each car from the starting point to the catching point is the same for both cars.
Step-by-step explanation: