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3 years ago

Round to the nearest Cent.

2 answers:

5 0

1. $.0999 = $.1

2. $2.0192 = $2.02

3. $21.5953 = $21.60

4. $35.6667 = $35.67

5. $1.3999 = $1.40

6. $25.3333 = $25.33

kompoz [17]3 years ago

3 0

1- $0.01 2- $2.02 3- $21.60 4- $35.67 5- $1.40 6- $25.33

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Locating Zeros of Polynomial Function: Approximate the real zeros to the nearest tenth

solmaris [256]

we are given

$f(x)=2x^4-x^3+x-2$

we can check each options

option-A:

-1,1

we can plug x=-1 and x=1 and check whethet f(x)=0

At x=-1:

$f(-1)=2(-1)^4-(-1)^3+(-1)-2$

$f(-1)=0$

At x=1:

$f(1)=2(1)^4-(1)^3+(1)-2$

$f(1)=0$

so, this is TRUE

option-B:

0,1

we can plug x=0 and x=1 and check whethet f(x)=0

At x=0:

$f(0)=2(0)^4-(0)^3+(0)-2$

$f(0)=-2$

At x=1:

$f(1)=2(1)^4-(1)^3+(1)-2$

$f(1)=0$

so, this is FALSE

option-C:

-2,-1

we can plug x=-2 and x=-1 and check whethet f(x)=0

At x=-2:

$f(-2)=2(-2)^4-(-2)^3+(-2)-2$

$f(-2)=36$

At x=-1:

$f(-1)=2(-1)^4-(-1)^3+(-1)-2$

$f(-1)=0$

so, this is FALSE

option-D:

-1,0

we can plug x=-1 and x=0 and check whethet f(x)=0

At x=-1:

$f(-1)=2(-1)^4-(-1)^3+(-1)-2$

$f(-1)=0$

At x=0:

$f(0)=2(0)^4-(0)^3+(0)-2$

$f(0)=-2$

so, this is FALSE

5 0

3 years ago

What is the sum of the exterior angle measures for an irregular convex hexagonal?

IceJOKER [234]

I think that the answer is A.

3 0

3 years ago

Ted walked 5/8 mile to his soccer game then he walked 3/8 mile to his friends house which distance is shorter

tatiyna

3/8 because he walked longer when he went to his soccer game

5 0

3 years ago

Suppose h(x)=3x-2 and j(x) = ax +b. Find a relationship between a and b such that h(j(x)) = j(h(x))

sergejj [24]

Answer:

$\displaystyle a = \frac{1}{3} \text{ and } b = \frac{2}{3}$

Step-by-step explanation:

We can use the definition of inverse functions. Recall that if two functions, f and g are inverses, then:

$\displaystyle f(g(x)) = g(f(x)) = x$

So, we can let j be the inverse function of h.

Function h is given by:

$\displaystyle h(x) = y = 3x-2$

Find its inverse. Flip variables:

$x = 3y - 2$

Solve for y. Add:

$\displaystyle x + 2 = 3y$

Hence:

$\displaystyle h^{-1}(x) = j(x) = \frac{x+2}{3} = \frac{1}{3} x + \frac{2}{3}$

Therefore, a = 1/3 and b = 2/3.

We can verify our solution:

$\displaystyle \begin{aligned} h(j(x)) &= h\left( \frac{1}{3} x + \frac{2}{3}\right) \\ \\ &= 3\left(\frac{1}{3}x + \frac{2}{3}\right) -2 \\ \\ &= (x + 2) -2 \\ \\ &= x \end{aligned}$

And:

$\displaystyle \begin{aligned} j(h(x)) &= j\left(3x-2\right) \\ \\ &= \frac{1}{3}\left( 3x-2\right)+\frac{2}{3} \\ \\ &=\left( x- \frac{2}{3}\right) + \frac{2}{3} \\ \\ &= x \stackrel{\checkmark}{=} x\end{aligned}$

3 0

2 years ago

I’m not sure about this one folks plz help:D

solong [7]

35 is the answer

Explanation, the sum of interrior angme is 180degree

x+(3x+40)= 180

or, 4x= 180-40

or, x= 140÷ 4

or x = 35

8 0

3 years ago

Read 2 more answers