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Galina-37 [17]
3 years ago
5

B) Find the standard deviation of the number of nights potential customers will need.

Mathematics
1 answer:
Fofino [41]3 years ago
4 0

Answer:

ok

Step-by-step explanation:

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FIRST ANSWER GETS BRAINLIEST!!<br> (sorry for the colors on the picture)
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2 years ago
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5. Of the 3 times Buddy kisses Jovie while they
Wewaii [24]

Answer:

2/3 times he kissed her 1/3 times he missed

Step-by-step explanation:

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3 years ago
If you can help me that would be great the instructions are to factor these polynomial Don’t answer just to get pointsNO LINKS!!
natima [27]

Answer:

3. 3(x+y)(x-y)

4. (y²+4)(y+2)(y-2)

5. 2(3x+1)(x+2)

Step-by-Step:

3. 3(x²-y²) = 3(x+y)(x-y)

4. y⁴-16 = (y²+4)(y²-4)= (y²+4)(y+2)(y-2)

5. 6x²+14x+4 = 2(3x²+7x+2) = 2(3x+1)(x+2)

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4 0
2 years ago
<img src="https://tex.z-dn.net/?f=5xy%20%7B%20-%20x%7D%20%5E%7B2%7D%20%7Bt%7D%20%20%2B%202xy%20%2B%203x%20%7B%7D%5E%7B2%7D%20t"
fenix001 [56]

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Step-by-step explanation:

6 0
1 year ago
A population of 100 frogs increases at an annual rate of 22%. How many frogs will there be in 5 years? Write an expression to re
gizmo_the_mogwai [7]
Exponential growth of the form:

F=Ar^t

F=100(1.22)^t

F(5)=100(1.22)^5

F(5)=270.27

F(5)=270 to the nearest frog...

....

1.22=r^12

r=1.22^(1/12)

F=100(1.22^(1/12)^t)

F=100(1.22^(t/12))  now it will produce monthly populations...

Say we did the same as before but instead of 5 years you have 60 months...

F(60)=100(1.22^(60/12))

F(60)=270 to the nearest frog... :P 
6 0
3 years ago
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