As per the gas equation:
P = ( n ) ( R ) ( T ) / ( V )
n = number of moles
R = Gas Constant = 0.08206 atm - L / gmol - K
T = Temperature in Kelvin
V= Volume in meters
P = ( n ) ( R ) ( T ) / ( V )
P = {0.55 gmol x 0.08206 atm - L / gmol - K x 305 K }/ 8.5 L
P = 1.62 atm
Answer:
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Cottage and Small Industries Development Committee to organize National Industrial Goods and Technology Expo
By Glocal Khabar - 2368 0
National Industrial Goods and Technology Expo- Glocal Khabar
Kathmandu, February 19, 2018: Cottage and Small Industries Development Committee is set to organize the twenty-ninth edition of National Industrial Goods and Technology Expo from March 23, 2018 at Bhrikutimandap, Kathmandu.
The motto of the five-day event is ‘Let’s use home-made products, move ahead towards prosperity.’ The committee has shared that handicrafts, wool and bamboo products, goods made from handmade papers, different types of pickles and Palpali Dhaka would be put on display in the expo.
Answer:
The reading of the experiment made in air is 50 g more than the reading of the measurement made in water.
Explanation:
Knowing that the density of lead is and the volume, we can calculate the true weight of the piece of lead:
When the experiment is done in air, we can discard buoyancy force (due to different densities) made by air because it's negligible and the measured weight is approximately the same as the true weight.
When it is done in water, the effect of buoyancy force (force made by the displaced water) is no longer negligible, so we have to take it into account.
Knowing that the density of water is 1 g per cubic centimeter, and that the volume displaced is equal to the piece of lead (because of its much higher density, the piece of lead sinks), we can know that the buoyancy force made by water is 50 g, opposite to the weight of the lead.
Now that we have the two measurements, we can calculate the difference:
The reading of the experiment made in air is 50 g more than the reading of the measurement made in water.
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