Two waves interfere when they run into each other.
The barrier reflects waves that run straight into it. It acts as a wave source and sends wave pulses back up the page towards the incoming waves.
Imagine a loose string tied to a wall. Someone sends two consecutive pulses along the string towards the wall. The first pulse gets reflected right away. It will travel backward towards the person holding the string. Along its way, it will run into the second pulse. The two pulses will interfere. The wall will make the reflected pulse out of phase with the second one. They will end up creating a destructive interference.
So is the case with the water waves running into the barrier. The barrier will send incoming waves back toward where they came from. Reflected waves interfere with incoming ones.
Answer:
μ =5.40 A-m²
Explanation:
The components of the net magnetic field are the magnetic field of the dipole and the magnetic field of Earth, then from the right triangle, the deflection angle is computed by
tan θ = Bdipole / Bearth ⇒ Bdipole = Bearth* tan θ
Bdipole = 2e-5 T*tan 70° = 5.49e-5 T
The magnetic field at the location of the compass due to the dipole has a magnitude
Bdipole = (μ₀/4π)(2μ/r³) ⇒ μ = Bdipole r³ / 2(μ₀/4π)
μ = (5.49e-5 T)(0.27m)³ / 2(1 × 10−7 T m² /(C m/s)) = 5.40 A-m²
Answer: 4850N
Explanation:
Mass of car = 970 kg
Time = 5 s
Speed = 25 m/s
Average force exerted on the car = ?
Recall that Force is the product of the mass of an object and the acceleration by which it moves
i.e Force = mass x acceleration
(Since, acceleration is the rate of change of velocity or speed per unit time)
i.e Acceleration = Speed / Time
Acc = 25m/s / 5s
Acc = 5m/s^2
Average force = mass x acceleration
Avg force = 970 kg x 5m/s^2
= 4850N
Thus, the average force exerted on the car is 4850 Newton
To solve this problem we will apply the concept given by the law of gravitational attraction, which properly defines gravity under the function
Here,
G = Gravitational Universal Constant
M = Mass of Earth
r = Distance between the human and the center of mass of the Earth
The acceleration due to gravity when is 4 times the mass of Earth and 3 times the radius would be given as,
The weight is defined as
So the new weight would be given as
Therefore the weight under this condition is 288.8N
D would be correct.
Have a merry Christmas!
