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mario62 [17]
3 years ago
14

when using substitution to solve a system of education, how can you tell when a system has no solution

Mathematics
1 answer:
OLEGan [10]3 years ago
4 0

Answer:

Recognize systems of equations that have no solution or an infinite number of solutions



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Between with pair of numbers is the exact product of 379 and 8
VikaD [51]

Answer:


Step-by-step explanation:

379 is a prime number.  Only 2 numbers will divide into it. 1 and 379

So you could do this

379 * 8 = 3032

(379 * 2  ) * 4 = 758 * 4 = 3032

(379 * 4 ) * 2 = 1516 * 2 = 3032


7 0
3 years ago
(−7c+8d)0.6 distributive property
Ksivusya [100]

We are given

(-7c+8d)0.6

we can use distribute property

Distributive property:

(A+B)C=A*C+B*C

so, we can write it as

(-7c+8d)0.6=-7c*0.6+8d*0.6

(-7c+8d)0.6=-7*0.6c+8*0.6d

now, we can multiply terms

and we get

(-7c+8d)0.6=-4.2c+4.8d..............Answer


4 0
3 years ago
Read 2 more answers
Please help thanks in advance
Galina-37 [17]

Answer:

43.25

Step-by-step explanation:

Since sides DF and FE are congruent, their opposite angles D and E are also congruent.

m<D + m<E + m<F = 180

x + x + 93.5 = 180

2x = 86.5

x = 43.25

Answer: 43.25

7 0
3 years ago
CAN SOME ONE PLZ HELP I NEED HELP
Romashka [77]

Answer:

9

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
The three medals earned in the Olympics are the gold, silver, and bronze medals. In the 2014 Winter Olympics, the United States
marta [7]

Answer:

Let x be the number of silver medals.

As there were two more gold medals than silver ones, gold medals are x+2

We also know that the number of bronze medals was 4 less than the sum of gold and silver, so if there are x + 2 of gold and x of silver, there are x+x+2-4 of bronze.

Now, we can do an equation, as we know there were a total of 28 medals:

x + x + 2 + x + x + 2 - 4 = 28

And we isolate x:

4x = 28

x = 28/4 = 7

There were 7 silver medals, so there were 9 gold ones (7-2) and 12 of bronze (9+7-4).

4 0
3 years ago
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