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4 years ago

Compare and contrast weight and mass

Physics

1 answer:

DerKrebs [107]4 years ago

6 0

mass is amount of something kg

weight is grav force of something pulled by a planet, say. N

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A proton with a speed of 3.000×105 m/s has a circular orbit just outside a uniformly charged sphere of radius 7.00 cm. What is t

Rama09 [41]

To solve this problem we will apply the principles of energy conservation. The kinetic energy in the object must be maintained and transformed into the potential electrostatic energy. Therefore mathematically

$KE = PE$

$\frac{1}{2} mv^2 = \frac{kq_1q_2}{r}$

Here,

m = mass (At this case of the proton)

v = Velocity

k = Coulomb's constant

$q_{1,2}$ = Charge of each object

r= Distance between them

Rearranging to find the second charge we have that

$q_2 = \frac{\frac{1}{2} mv^2 r}{kq_1}$

Replacing,

$q_2 = \frac{\frac{1}{2}(1.67*10^{-27})(3*10^5)^2(7*10^{-2})}{(9*10^9)(1.6*10^{-19})}$

$q_2 = 3.6531nC$

Therefore the charge on the sphere is 3.6531nC

4 0

3 years ago

Suppose we could shrink the Earth without changing its mass. At what fraction of its current radius would the free-fall accelera

spin [16.1K]

Answer:

$R' = \frac{1}{\sqrt{3}}R$

Explanation:

The acceleration due to gravity on the surface of the Earth is given by:

$g=\frac{GM}{R^2}$

where

G is the gravitational constant

M is the mass of the Earth

R is the radius of the Earth

Here we want to find the new Earth radius R' for which the gravitational acceleration at the surface, g', would be 3 times the current value of g:

$g' = 3g$

So we would have

$\frac{GM}{R'^2}=3(\frac{GM}{R^2})$

Solving the equation for R', we find

$R'^2 = \frac{1}{3}R^2\\R' = \frac{1}{\sqrt{3}}R$

7 0

3 years ago

Read 2 more answers

Why don't you notice your gravitational force on other objects?

mixas84 [53]

The answer is B tell me if I am wrong.

4 0

3 years ago

Read 2 more answers

Light traveling through plate glass (n = 1.52) approaches the surface, i.e. the air-glass interface. What minimum incident angle

Ilia_Sergeevich [38]

Answer:

41°

Explanation:

refractive index of glass, n = 1.52

For total internal reflection, the angle of refraction in rarer medium is 90°.

r = 90°

Let the angle of refraction in denser medium, that means in glass is i.

By use of Snell's law

refractive index of rarer medium with respect to denser medium, that means refractive index of air with respect to glass = 1 / n

And

$\frac{1}{n}=\frac{Sin i}{Sin r}$

$\frac{1}{1.52}=\frac{Sin i}{Sin 90}$

$0.658= Sin i$

i = 41°

Thus, the angle of incidence should be 41°.

8 0

3 years ago

A badminton player shuffles his shoes in resins explain the scientific reason behind this

Kobotan [32]

Answer:

To avoid slipping while playing badminton or to increase friction between the shoes and the badminton court or to enhance the grip.

Explanation:

As the question is general so I will try answer it generally.

As badminton court is usually slippery and flat with no or very little friction and while playing badminton, players have to move very fast from place to place.

So, in order to effectively move faster to take the difficult shots with accuracy badminton players increase the friction between their shoes and the badminton court by shuffling resin to their shoes. It helps to enhance the grip.

4 0

3 years ago