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Leona [35]
1 year ago
9

what gauge pressure in the water pipes is necessary if a fire hose is to spray water to a height of 16 m?

Physics
1 answer:
bogdanovich [222]1 year ago
6 0

1.568 atm gauge pressure in the water pipes is necessary if a fire hose is to spray water to a height of 16 m

Gauge pressure = ρgh

                          = 1000 × 9.8 × 16

                           = 156800 Pa

                           = 1.568 atm

The pressure measured in relation to the surrounding atmospheric pressure is known as gauge pressure. A diaphragm sensor can be used to detect gauge pressure, with one side of the diaphragm exposed to the pressure medium that has to be measured and the other exposed to the surrounding atmospheric pressure.

It should be noted that while measuring gauge pressure, unless the measuring site is exposed to ambient air pressure, the measured gauge pressure will alter with fluctuations in barometric pressure caused by changes in weather patterns.

Learn more about Pressure here:

brainly.com/question/29341536

#SPJ4

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If a projectile is launched vertically from the Earth with a speed equal to the escape speed, how high above the earth's surface
Alecsey [184]

Answer: h = 3R

Explanation:

Using the law of conservation of energy,

Total energy at the beginning of the launch would be equal to total energy at any point.

kinetic energy + gravitational potential energy = constant

Initial energy of the projectile =\frac{1}{2}mv_e^2-\frac{GMm}{R}... (1)

where R is the radius of the Earth, M is the mass ofthe Earth, m is the mass of the projectile.

escape velocity, v_e=\sqrt{\frac{2GM}{R}}

Total energy at height h above the Earth where speed of the projectile is half the escape velocity:

\frac{1}{2}m(v_e/2)^2-G\frac{Mm}{R+h} ...(2)

(1)=(2)

⇒\frac{1}{2}m(v_e/2)^2-G\frac{Mm}{R+h} = \frac{1}{2}mv_e^2-\frac{GMm}{R}

⇒G\frac{Mm}{R}-G\frac{Mm}{R+h}= \frac{1}{2}m \frac{3}{4}v_e^2 =\frac{1}{2}m \frac{3}{4} (\sqrt{\frac{2GM}{R}})^2

⇒\frac{GM(R+h-R)}{R(R+h)} = \frac{3}{4}(\frac{GM}{R})

⇒\frac{h}{R+h} = \frac{3}{4}

⇒h = 3R

Thus, at height equal to thrice radius of Earth, the speed of the projectile would reduce to half of escape velocity.  

4 0
3 years ago
Read 2 more answers
An 88.0 kg passenger is inside a 1450.0 kg elevator that rises 30.0 m in exactly 1.0 minutes. How much power is needed for the e
OleMash [197]

Answer:

Explanation:

6 0
3 years ago
Air at 30°C and 2MPa flows at steady state in a horizontal pipeline with a velocity of 25 m/s. It passes through a throttle valv
erastovalidia [21]

Answer:

V_2=159.9\ m/s

T_2=290.6K

Explanation:

At initial condition

P=2 MPa

T=30°C

V=25 m/s

At final condition

P=0.3 MPa

Now from first law for open system

h_1+\dfrac{V_1^2}{2000}=h_2+\dfrac{V_2^2}{2000}

We know that for air

h= 1.010 x T  KJ/kg

1.01\times 303+\dfrac{25^2}{2000}=1.01\times T+\dfrac{V_2^2}{2000}                               -----1

Now from mass balance

\rho_1A_1V_1=\rho_2A_2V_2

We also know that

\rho=\dfrac{P}{RT}

\dfrac{P_1}{RT_1}V_1=\dfrac{P_2}{RT_2}V_2

\dfrac{2}{R\times 303}\times 25=\dfrac{0.3}{RT_2}V_2

T_2=1.81V_2                  ----------2                                                                                                

Now from equation 1 and 2

V_2^2+3673.749V-612916.49=0

So we can say that

V_2=159.9\ m/s

This is the outlet velocity.

Now by putting the values in equation 2

T_2=1.81\times 159.9  

T_2=290.6K

This is the outlet temperature.

4 0
4 years ago
The gravitational force on a baseball is 1.4 N. What is its mass? Round to two decimal places.
valina [46]

Answer:

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Explanation:

W = mg

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m = 0.14 kg

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Why are household wall sockets alternating current (AC) instead of direct current (DC)? Select all that apply.
Bond [772]

Answer:

It is easier to scale the voltage of AC from high to low and low to high than with DC

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