Answer:
(b) In ideal condition we neglect mass of spring but in real springs mass of spring adds another factor to its time period.
since we are adding a factor of mass to the system, and frequency being inversely proportional to squared root of mass, we can come to a general conclusion that it effectively reduces the natural frequency .
Explanation:
kindly check the attachment for explanation.
Answer:
B. 7.07 m/s
Explanation:
The velocity of the stone when it leaves the circular path is its tangential velocity, , which is given by
where is the angular speed and
is the radius of the circular path.
is given by
where is the frequency of revolution.
Thus
Using values from the question,
<em>Note the conversion of 75 cm to 0.75 m</em>
Answer:
a)
b)
c)
d)
e)
Explanation:
Given that:
(a)
∵ 1 rev = 2π radians
∴ angular speed ω:
where N = angular speed in rpm.
putting the respective values from case 1 we've
(c)
using the equation of motion:
here α is the angular acceleration
(b)
using the equation of motion:
(d)
using equation of motion:
(e)
using the equation of motion: