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Rus_ich [418]
3 years ago
14

What is the velocity of an object that has been in free fall for 2.5

Physics
1 answer:
Vladimir79 [104]3 years ago
8 0

Answer: calculate the free fall distance and velocity without air resistance from, the free fall.

Explanation:

To find out something's speed (or velocity) after a certain amount of time, you just multiply the acceleration of gravity by the amount of time since it was let go of. So you get: velocity = -9.81 m/s^2 * time, or V = gt. The negative sign just means that the object is moving downwards

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¿Cuál de las siguientes magnitudes es derivada?
Sedaia [141]

Answer:

A. El volumen

B. La densidad.

Explanation:

A derived quantity is defined as one that has to be calculated by using two or more other measurements.

Volume is a derived quantity because it requires one to use different measurements to determine it. For instance, in the case of a cube, the length, width and height of the cube are all needed to calculate volume.

Density is also a derived quantity because it needs both volume and mass for it to be calculated.

8 0
3 years ago
How does increasing the distance between charged objects affect the electric force between them?
Brums [2.3K]

Answer:In electrostatics, the electrical force between two charged objects is inversely related to the distance of separation between the two objects. Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects.

Explanation:

hope it helps

4 0
3 years ago
Suppose that a comet that was seen in 550 A.D. by Chinese astronomers was spotted again in year 1941. Assume the time between ob
pickupchik [31]

To solve the problem it is necessary to apply the concepts related to Kepler's third law as well as the calculation of distances in orbits with eccentricities.

Kepler's third law tells us that

T^2 = \frac{4\pi^2}{GM}a^3

Where

T= Period

G= Gravitational constant

M = Mass of the sun

a= The semimajor axis of the comet's orbit

The period in years would be given by

T= 1941-550\\T= 1391y(\frac{31536000s}{1y})\\T=4.3866*10^{10}s

PART A) Replacing the values to find a, we have

a^3= \frac{T^2 GM}{4\pi^2}

a^3 = \frac{(4.3866*10^{10})^2(6.67*10^{-11})(1.989*10^{30})}{4\pi^2}

a^3 = 6.46632*10^{39}

a = 1.86303*10^{13}m

Therefore the semimajor axis is 1.86303*10^{13}m

PART B) If the semi-major axis a and the eccentricity e of an orbit are known, then the periapsis and apoapsis distances can be calculated by

R = a(1-e)

R = 1.86303*10^{13}(1-0.997)

R= 5.58*10^{10}m

7 0
3 years ago
Suppose you have a 113-kg wooden crate resting on a wood floor. (μk = 0.3 and μs = 0.5) (a) What maximum force (in N) can you ex
AURORKA [14]

Answer:

554.27N

Explanation:

(a)  The max frictional force exerted horizontally on the crate and the floor is,

Substitute the values,

μs=0.5

mass=113kg

g=9.81m/s

Ff=μsN

   =μsmg

   =(0.5 x 113 x 9.81)

Ff=554.27N

3 0
3 years ago
The shiny surface of a CD is imprinted with millions of tiny pits, arranged in a pattern of thousands of essentially concentric
AURORKA [14]

Answer:

Distance between two concentric circles is in radius d = 1.0 um

Explanation:

Given:

- Wavelength of light λ = 680 nm

- Distance of disc from screen x = 1.5 m

- Separation between central and first order y = 1.4 m

- Angle Q is between central order and mth order

Find:

What is the distance between the circles on the CD’s surface? - d?

Solution:

- The relationship between and wavelength and the position of fringes with respect to diffraction grating is given by Youns's experiment as follows:

                                     sin (Q) = m*λ / d

- Compute the angle Q for first order m = 1:

                                     sin(Q) = 1.4 / sqrt(1.4^2 + 1.5^2)

                                     sin(Q) = 1.4 / 2.05183

                                     sin(Q) = 0.68232

- Use the above result and compute for the grating d for m =1 :

                                     d = λ / sin(Q)

                                     d = 680*10^-9 / 0.68232

                                     d = 1.0 um

-  Since the circles are concentric the difference in radius is d = 1.0 um

3 0
3 years ago
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