If in a number plate two different alphabets need to be selected then there are 650 such number plates that can be formed in such a way that the alphabets come in increasing order.
Given that a number plate can be formed using 2 alphabets which must come in increasing order.
We are required to find the number of plates that can be formed.
Number of total alphabets=26.
The number of plates will be equal to the number of ways in which two alphabets can be arranged.
Combination is the number of ways in which some combinations can be formed. It is expressed as n
=n!/r!(n-r)!
Number of license plates=26
*25
=26*25
=650 plates
Hence If in a number plate two different alphabets need to be selected then there are 650 such number plates that can be formed in such a way that the alphabets come in increasing order.
Learn more about combinations at brainly.com/question/11732255
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Answer:
wrong it is 667.95
Step-by-step explanation:
If we intersect the circle of radius 1 around (4,-4) and the circle of radius 1 around (4,-6) they'll intersect at the center of circle radius 1 that has both those points.
Here we don't really have to do any math. It's clear that the midpoint (4,-5) is 1 away from both (4,-4) and (4,-6) so that's our answer:
Answer: (4,-5)
Answer:
check image below
Step-by-step explanation:
The answer is the first option. 7 left is not - 7 in this case. With these questions, you switch the signs. The vertical movement signs stay the same. Therefore, the answer is the first option.