Question

a starting lineup in a basketball consists of two guards, two forwards, and a center. a. a certain college team has on its roster 4 centers, 5 guards, 5 forwards, and one individual (x) who can play either guard or forward. how many different starting lineups can be created? (hint: consider lineups without x, then lineups with x as guard, then lineups with x as foward.)

Answer 1

Different starting lineups can be created - 120+60+120=300. A certain college team has on its roster 4 centers, 5 guards, 5 forwards, and one individual (x) who can play either guard or forward.

1. A lineup without x is an example. You must decide.

• 5 quards, 2 guards;

• two of the three forwards;
• from 4 centers, 1 center.

It can be made as -

2C5 × 2C3× 1C4 = 10× 3×4 = 120 ways

2. Consider starting lineups with guard x. You must decide.

• 2 guards chosen from 6 quards (at least one of them must be x);

• two of the three forwards;
• from 4 centers, 1 center.

1C5×2C3×1C4 = 5×3×4 = 60 ways

3. Think about lineups where x is the forward. You must decide.

• 5 quards, 2 guards;
• 2 forwards from 4 forwards (x must be one of them);
• from 4 centers, 1 center.

2C5×1C3×1C4 = 10×3×4 = 120 ways.

Therefore, total number different lineups is - 120+60+120=300.

To learn more about combinations from given link

brainly.com/question/8781187

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