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natka813 [3]
3 years ago
5

Please I really need the answer for this

Mathematics
2 answers:
sasho [114]3 years ago
8 0

The answer is A it is correct.

RideAnS [48]3 years ago
8 0

Answer: THE OBJECT MUST MOVE IN THE SAME DIRECTION AS THE FORCE. WORK IS DONE ON AN OBJECT IF TWO THINGS OCCUR 1. THE OBJECT MOVES AS A FORCE IS APPLIED 2. THE DIRECTION OF THE OBJECT'S MOTION IS THE SAME AS THE DIRECTION OF THE FORCE APPLIED.

Step-by-step explanation:

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Please help me withe this proof as well.​
baherus [9]

- D is the midpoint of AB, E is the midpoint of BC

Answer: A. Given

I left off DB||FC because that's not given.  But we can construct it.

Construct line through C parallel to AB.  Extend DE to intersect and call the meet F.

- DB || FC

By Construction

----

- Angle B congruent to angle FCE

Answer: D. Alternate Interior Angles

We have transversal BC across parallel lines AB and CF, so we get congruent angles ABC and FCB aka FCE

- angle BED congruent to angle CEF

Answer: H. Vertical angles are congruent

When we get lines meeting like this we get the usual congruent and supplementary angles.

- Triangle BED congruent to Triangle CEF

Answer: F. Angle Side Angle

We have BE=CE, DBE=FCE, BED=CEF

- DE congruent to FE and DB congruent to FC

Answer: C. CPTCTF

Corresponding parts ...

- AD congruent to DB and DB congruent to FC therefore AD congruent to FC

Answer: E. Transitive Property of Congruent

Things congruent to the same thing are congruent

- ADFC is a parallelogram

Answer: G.  AD and FC are congruent and parallel

Presumably this is a theorem we have already established.

- DE || AD

Answer: B. Definition of a parallelogram

4 0
3 years ago
This is number three Nd I neeed help with this I can help you with anything
KATRIN_1 [288]

Answer:

a. False

b. False

c. True

d. True

e. True

5 0
3 years ago
Can u please help me?!?!
ivolga24 [154]

Answer:

Step-by-step explanation: yes

8 0
3 years ago
A tank contains 3,000 L of brine with 15 kg of dissolved salt. Pure water enters the tank at a rate of 30 L/min. The solution is
Shalnov [3]

Answer:

Step-by-step explanation:

Volume of tank is 3000L.

Mass of salt is 15kg

Input rate of water is 30L/min

dV/dt=30L/min

Let y(t) be the amount of salt at any time

Then,

dy/dt = input rate - output rate.

The input rate is zero since only water is added and not salt solution

Now, output rate.

Concentrate on of the salt in the tank at any time (t) is given as

Since it holds initially holds 3000L of brine then the mass to volume rate is y(t)/3000

dy/dt= dV/dt × dM/dV

dy/dt=30×y/3000

dy/dt=y/100

Applying variable separation to solve the ODE

1/y dy=0.01dt

Integrate both side

∫ 1/y dy = ∫ 0.01dt

In(y)= 0.01t + A, .A is constant

Take exponential of both side

y=exp(0.01t+A)

y=exp(0.01t)exp(A)

exp(A) is another constant let say C

y(t)=Cexp(0.01t)

The initial condition given

At t=0 y=15kg

15=Cexp(0)

Therefore, C=15

Then, the solution becomes

y(t) = 15exp(0.01t)

At any time that is the mass.

5 0
3 years ago
Which equation can be used to find the measure of Arc E H G?
anygoal [31]

Answer:

I need more context ,like the graph to figure this out.

Step-by-step explanation:

5 0
2 years ago
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