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AlexFokin [52]
3 years ago
6

(9/16)^−1/2 How do I solve this equation?

Mathematics
1 answer:
vlada-n [284]3 years ago
4 0
\left(\dfrac{9}{16}\right)^{-\tfrac{1}{2}}=\\
\left(\dfrac{16}{9}\right)^{\tfrac{1}{2}}=\\
\sqrt{\dfrac{16}{9}}=\\
\dfrac{4}{3}
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How to write a polynomial function with rational coefficients in standard form with the given zeros?
Gennadij [26K]
If you have as many zeros (z1, z2,... zn) as the degree of the polynomial function (n), then the function equation is given by:

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You might also have less zeros than the degree of the polynomial, because some of them have a multiplicity greater than 1. Let z1,...,zr be the zeros, and m1,...mr be the multiplicity of each zero, where m1+m2+...+mr=n (we assume the sum of all multiplicities equals the degree of the polynomial). In this case, you can use:

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Savatey [412]

If f(x) + g(x) = (f + g)(x), then we can simplify this by adding both functions together: ΙxΙ + 9 + (- 6). This makes ΙxΙ + 3. The absolute value of x can only be something that is greater than or equal to zero for the function to make sense. This means your answer is a.) (f + g)(x) ≥ 3.

4 0
4 years ago
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