(9/16)^−1/2 How do I solve this equation?

1 answer:

4 0

$\left(\dfrac{9}{16}\right)^{-\tfrac{1}{2}}=\\
\left(\dfrac{16}{9}\right)^{\tfrac{1}{2}}=\\
\sqrt{\dfrac{16}{9}}=\\
\dfrac{4}{3}$

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Hey there, Bulgogi!

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