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stich3 [128]
3 years ago
15

PLEASE HELP !!!

Mathematics
1 answer:
kobusy [5.1K]3 years ago
7 0
Help with what. Hahahaha
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Which strategy best explains how to solve this problem?
Rufina [12.5K]
This is a geometric sequence because each term is twice the value of the previous term.  So this is what would be called the common ratio, which in this case is 2.  Any geometric sequence can be expressed as:

a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number

In this case we have r=2 and a=1 so

a(n)=2^(n-1)  so on the sixth week he will run:

a(6)=2^5=32

He will run 32 blocks by the end of the sixth week.

Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:

s(n)=a(1-r^n)/(1-r)  where the variables have the same values so

s(n)=(1-2^n)/(1-2)

s(n)=2^n-1 so 

s(6)=2^6-1

s(6)=64-1

s(6)=63 blocks

So he would run a total of 63 blocks in the six weeks.
4 0
3 years ago
Read 2 more answers
George bought 30 packs of football cards.There were 14 cards in each pack.How many cards did George buy
emmainna [20.7K]

Answer:

there would be 420 cards in total

Step-by-step explanation:


6 0
3 years ago
I will give decent points if corrected
s2008m [1.1K]

Answer:

it's either a or b, but I would go with A

5 0
3 years ago
Read 2 more answers
Anyone know the answer?
kherson [118]

Answer:

A≈18.38

Step-by-step explanation:

Solve for area

Shape: Parallelogram

Formula: Base*Height

5.25*3.5=18.375

Round answer

Hope this helps.

6 0
3 years ago
a shipment of sugar fills 4 1/3 containers. if each container holds 2 1/7 tons of sugar, what is the amount of sugar in the enti
emmasim [6.3K]

To find the answer we need multiply the number of containers by number tons of sugar each container has.

(4 1/3 )*(2 1/7).

To calculate , we need to convert mixed numbers into improper fractions.

4 1/3 = (4*3 +1)/3 = 13/3

2 1/7 = (2*7+1)/7 =15/7

(4 1/3 )*(2 1/7) = (13/3) * (15/7) = (13*5)/7 = 65/7 = 9 2/7 (tons)

Answer: 9 2/7 tons.


8 0
3 years ago
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