Answer:
109
Step-by-step explanation:
Formula
<ZHG + <IHZ = <IHG
Givens
<ZHF = 11x - 1
<IHZ = 24
<IHG = 12x + 13
Solution
11x - 1 + 24 = 12x + 13 Combine terms on the left
11x + 23 = 12x + 13 Subtract 13 from both sides
<u> - 13 - 13 </u>
11x + 10 = 12x Subtract 11x from both sides
<u>-11x -11x</u>
10 = x
Answer
11x - 1 = 11*10 - 1 = 110 - 1 = 109
Answer:
Elimination method
Step-by-step explanation:
We have a choice to eliminate the y or x:
I chose x
So now we double the second equation to make the co efficient of x the same:
6x-5y = -3
6x+4y = 24
Now we subtract both equations to eliminate the x's:
6x-5y = -3
- - -
6x+4y = 24
-9y = -27
y = 3
Now we substitute this value into either equation 1 or 2:
I chose 2
3x + 2(3) =12
Simplify:
3x + 6 =12
Subtract 6 from both sides:
3x + 6 -6 = 12 -6
Simplify:
3x = 6
Divide both sides by 3:
3x÷3 = 6÷3
Simplify:
x = 2
This is true, it's A!
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Answer:
- 15
Step-by-step explanation:
Given f(x) divided by (x + h) then the remainder is the value of f(- h)
Here
f(x) = 3x³ - 5x² - 47x + k ← k is the constant term , then
f(- 3) = 3(- 3)³ - 5(- 3)² - 47(- 3) + k = 0 , that is
3(- 27) - 5(9) + 141 + k = 0
- 81 - 45 + 141 + k = 0
15 + k = 0 ( subtract 15 from both sides )
k = - 15