Answer:
21.V=1746.1
22.V=1922.7
23.V=54.4
Step-by-step explanation:
V=h*w*l V=pir^2*h
V=12*8*14 . V=pi*4^2*8
V=1344 . V=402.1
V1+V2=1344+402.1=1746.1
V=pi*r^2*h V=2/3*pi*r^3
V=pi*6^2*13 V=2/3*pi*6^3
V=pi*36*13 V=2/3*pi*216
V=1470.3 V=452.4
V1+V2=1470.3+452.4=1922.7
V=1/3pi*r^2*h V=1/3pi*r^2*h
V=1/3pi*2^2*6 V=1/3pi*2^2*7
V=8pi V=28/3pi
V=25.1 . V=29.3
V1+V2=25.1+29.3=54.4
With the help of the given equation, we know that the automobile is worth $12528.15 after four years.
<h3>
What are equations?</h3>
- A mathematical equation is a formula that uses the equals sign to represent the equality of two expressions.
- a formula that expresses the connection between two expressions on each side of a sign.
- Typically, it has a single variable and an equal sign.
- Like this: 2x - 4 Equals 2.
- In the above example, the variable x exists.
So, the equation of depreciation: y = A(1 - r)∧t
The current value is y.
A is the initial cost.
r is the depreciation rate.
t is the time in years, and
In four years, we must ascertain the present value.
Now,
y = $24000(1 - 0.15)⁴
y = 24000(0.85)⁴
y = 24000 × 0.52200625
y = 12528.15
Therefore, with the help of the given equation, we know that the automobile is worth $12528.15 after four years.
Know more about equations here:
brainly.com/question/28937794
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Complete question:
The general equation for depreciation is given by y = A(1 – r)t, where y = current value, A = original cost, r = rate of depreciation, and t = time, in years. The original value of a car is $24,000. It depreciates 15% annually. What is its value in 4 years? $
Use the Midpoint formula
Under a radical it would be
√ ( x↓2 - x↓1 ) ² + ( y↓2 - y↓1 ) ²
The down arrow is subscript -
So use the numbers from the two coordinates to plug in.
If you have any question comment :)
(1-52/2+5)=(1-26+5)=(-25+5)=-20
continuing:
-20*2*6*6= -40*6*6=-240*6=-1440
result: -1440
the answer is seven option c
