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3 years ago

12

How do I rewrite this expression in the form of k•y^n

1 answer:

saveliy_v [14]3 years ago

5 0

Answer:

6 · y^(-4/9)

Step-by-step explanation:

3 · 2 = 6

³√ = ^(1/3)

y^(-4/3) · y^(1/3) = y^(-4/9)

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Graph a line with a slope of 1/4 that contains the point (6, 3).

Semenov [28]

Answer:

The graph in the attached figure

Step-by-step explanation:

we know that

The equation of a line in point slope form is

$y-y1=m(x-x1)$

we have

$(x_1,y_1)=(6,3)$

$m=\frac{1}{4}$

substitute

$y-3=\frac{1}{4}(x-6)$

The easiest way to graph a line is to calculate the intercepts

The<u><em> x-intercept </em></u>is the value of x when the value of y is equal to zero

For y=0

$0-3=\frac{1}{4}(x-6)$

$-12=(x-6)$

$x=-12+6=-6$

The x-intercept is the point (-6,0)

The <u><em>y-intercept</em></u> is the value of y when the value of x is equal to zero

For x=0

$y-3=\frac{1}{4}(0-6)$

$y-3=-\frac{3}{2}$

$y=-\frac{3}{2}+3$

$y=1.5$

The y-intercept is the point (0,1.5)

Plot the intercepts and join the points to graph the line

(-6,0) and (0,1.5)

The graph in the attached figure

8 0

3 years ago

Write a integer for the situation a deposit of $145.50<br> Helpppp fast pleaseeeee

-Dominant- [34]

11.64 is the integer

8 0

3 years ago

Q7Which statement is incorrect for the graph of thefunction y = -5 cosGcos( 3 (x – 3)) +62The period is 4.The amplitude is 3.The

guajiro [1.7K]

The given function is,

$y=-5\cos (\frac{\pi}{2}(x-3))+6$

The graph can be drawn as,

The period will be distance between two consequetive maximas,

$\text{Period}=1-(-3)=4$

Thus, period is correct.

The amplitude can be determined as,

$\begin{gathered} Amplitude=\frac{\max -\min }{2} \\ =\frac{11-1}{2} \\ =5 \end{gathered}$

Thus, amplitue is incorrect.

The range is,

$y\in\lbrack1,11\rbrack$

Thus, the range is correct.

The midline is,

$\begin{gathered} \text{midline}=\frac{\max +\min }{2} \\ =\frac{1+11}{2} \\ =6 \end{gathered}$

Thus, the midline is correct.

Thus, option (b) is the solution.

5 0

1 year ago

Let f(x)=x2−2x−4 . What is the average rate of change for the quadratic function from x=−1 to x = 4?

goblinko [34]

Answer:

The average rate of change for f(x) from x=−1 to x = 4 is, 1

Step-by-step explanation:

Average rate A(x) of change for a function f(x) over [a, b] is given by:

$A(x) = \frac{f(b)-f(a)}{b-a}$

As per the statement:

$f(x) = x^2-2x-4$

we have to find the average rate of change from x = -1 to x = 4

At x = -1

$f(-1) = (-1)^2-2(-1)-4 = 1+2-4 = -1$

and

at x = 4

$f(4) = (4)^2-2(4)-4 = 16-8-4 = 4$

Substitute these in [1] we have;

$A(x) = \frac{f(4)-f(-1)}{4-(-1)}$

⇒ $A(x) = \frac{4-(-1)}{4+1}$

⇒ $A(x) = \frac{5}{5}$

Simplify:

A(x) = 1

Therefore, the average rate of change for f(x) from x=−1 to x = 4 is, 1

4 0

3 years ago

Read 2 more answers

A circle is centered at the point (7,1) and passes through the point (8,7). what is the radius

Scorpion4ik [409]

Easy

the radius is the distance from the center to a point on the circle

we are given
center=(7,1)
a point=(8,7)
find the distance
distance formula
D= $\sqrt{(x2-x1)^2+(y2-y1)^2}$

so the distance between point and center is radius
D= $\sqrt{(8-7)^2+(7-1)^2}$
D= $\sqrt{(1)^2+(6)^2}$
D= $\sqrt{1+36}$
D=√37 units

radius is √37 units

7 0

3 years ago