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4 years ago

How do I rewrite this expression in the form of k•y^n

Mathematics

1 answer:

saveliy_v [14]4 years ago

5 0

Answer:

6 · y^(-4/9)

Step-by-step explanation:

3 · 2 = 6

³√ = ^(1/3)

y^(-4/3) · y^(1/3) = y^(-4/9)

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I have 6 more questions and less than 20 minutes left for this test rjerirbrifirnem

ratelena [41]

X= 100 degrees. sorry if i answered too late

7 0

3 years ago

PLZ HELP 100PTS!!!!!!!!!!!

Sonja [21]

Answer:

GJK

Step-by-step explanation:

An inscribed angle is an angle formed by two line segments in a circle that intersect on the circle. The line segments must touch the circle at two points The angle must be on the circle itself.

GIH is not inscribed because I is in the center of the circle not on the circle

GJK is an inscribed angle GJ and JK touch the circle at two point and are inside the circle.

IGJ IG does not touch the circle at two points

JKL KL is outside the circle

8 0

3 years ago

Read 2 more answers

Which of the following functions has the largest value when x = 3? c(x) = 3x2 + 5x + 22 j(x) = 12x a(x) = 9x

Olin [163]

To determine the function which has the largest value at x=3,

We will calculate the value of each function by substituting the value of x=3 in each of the given function.

Let us consider the first function,

$c(x)=3x^{2}+5x+22$

$c(3)=3\times 3^{2}+5 \times 3+22$

$c(3)=27+15+22$

$c(3)=64$

Let us consider the second function,

$j(x)=12x$

$j(x)=12 \times 3 =36$

Let us consider the third function,

$a(x)=9x$

$a(x)=9 \times 3=27$

Therefore, the function c(x) has the largest value at x=3.

3 0

3 years ago

The repayment schedule is for a $1,300 loan at 7.5% for 6 months. What is the amount for interest at payment 5?

Jlenok [28]

Answer:

$2.77

Step-by-step explanation:

Here's one way to do it.

Data:

We must express the interest rate on a monthly basis.

i = 7.5 %/yr = 0.625 %/mo = 0.006 25

A = $1300

n = 6 mo

A. Monthly payments

The formula for the monthly payment (P) on a loan of A dollars that is paid back in equal monthly payments over n months, at an annual interest rate of i % is

$P = A(\frac{i}{1-(1+i)^{-n}})$

Calculation:

$P = 1300(\frac{0.006 25}{1-(1+0.006 25)^{-6}})$

$P = \frac{8.125}{{1- {1.006 25}}^{-6}}$

$P = \frac{8.125}{1 - 0.9633}$

$P = \frac{8.125}{0.03669}$

P = $221.43

B. Total amount paid over six months

Paid = 6 × 221.43

Paid = $1328.58

C. Amount paid after four months

Paid = 4 × 221.43

Paid = $885.72

D. Balance owed after four months

Owed = 1328.58 - 885.72

Owed = 1341.14 – 1121.08

Owed = $442.86

E. Interest included in Payment 5

I = Pi

I = 442.86 × 0.006 25

The interest included in Payment 5 is $2.77.

3 0

4 years ago

V2y + 3 = 11

spin [16.1K]

Answer:

v2y +3=11

V2y=11- 3

V2y=8

2y=8²

2y=64

y=64÷2

y=32 Answer

7 0

4 years ago