Answer:
Probability that event will have both red marbles will be 2.3% or 0.023.
Step-by-step explanation:
Given:
Total red marbles=5
Total blue marbles=25
Total number of marbles =30
To Find:
The probability that both are red without replacement of marbles.
Solution:
Now
Total sample space is 30 and total red marbles are 5
For a event that getting red marble probability is ,
=Total red marbles /total marbles.
=5/30
=1/6
So probability if getting red marble is 1/6
<em>Now for second chance there will be 4 red marbles remaining and 29 total marbles so,</em>
In second chance probability if getting red marble will be
=total red marbles present/total marbles remaining
=4/29
Now ,
The required probability will be getting both at a time
i.e probability getting red AND red marble so here AND operator which means multiple both the probability.
Probability both will have red =1/6*4/29
=4/(29*6)=2/(29*3)
=0.022988
=0.023
=2.3 %
This number is three billion, five hundred fifty-two million, three hundred eight thousand, seven hundred twenty-five.
The second 5 (from the left) is in the ten millions place. It has a value of 50,000,000.
Slope (y2-y1)/(x2-x1)
(10-0)/(10-8) = 10/2 = 5
The slope is 5
0,0 1,3 . 2,6 . 3,9 where x is the number of pages and y is the number of minutes
