Answer:
Since there are six possible outcomes, the probability of obtaining any side of the die is 1/6. The probability of rolling a 1 is 1/6, the probability of rolling a 2 is 1/6, and so on.
The sample space of the problem is 300 while the U' is equal to 100 as given. The given diagram also shows A and B separately so we can determine the part where the two coincides. The equation goes
120 + 50 + x + 100 = 300x = 30
Hence the probability is 30/ 300 or 10%
Given:
15 students
2 students must be chosen.
No repetition, no order
This is a combinations problem. We use this formula: n! / (n-r)!(r!)
n = 15 ; r = 2
15! / (15-2)!(r!) ⇒ 15! / 13! * 2! = 105
The factors of 33 are <u>1</u>, 3, <u>11</u>, and 33 .
The factors of 55 are <u>1</u>, 5, <u>11</u>, and 55 .
The <u>common</u> factors of 33 and 55 are 1 and 11 .
The<u> greatest</u> one is <em>11</em> .
1150, i’m pretty sure that’s it!
