Answer:
<h3>No.</h3>
Step-by-step explanation:
The sides would be unbalanced. To get the sides of a triangle, you have to add up the first two sides. The two sides combined usually have to be less than or equal to 15 to be considered "balanced". 22 is greater than 15, so that would leave you with an unbalanced triangle, sometimes considered degenerate. A degenerate triangle is a flat triangle that almost looks like a line. The triangle's vertices all lie on the same line, which makes it look very flat. That's why degenerate triangles are rarely considered "balanced" in regards to unit measures. So, given this is an unbalanced triangle, the answer to your question would be no.
Hope this helps!
Answer:
(-1, 4)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
10x + 6y = 14
-x - 6y = -23
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Elimination</em>
- Add 2 equations together: 9x = -9
- Divide 9 on both sides: x = -1
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: -x - 6y = -23
- Substitute in <em>x</em>: -(-1) - 6y = -23
- Multiply: 1 - 6y = -23
- Subtract 1 on both sides: -6y = -24
- Divide -6 on both sides: y = 4
Answer:
a) 25/324
b) 1/4
c) 1/3
Step-by-step explanation:
a) [⅓A + ⅓B]² = (⅓)²[A + B]²
= (1/9) [½ + ⅓]²
= (1/9)(⅚)²
= (1/9)(25/36)
= 25/324
b) ½ × ½ = ¼
c) (½ × ⅓) + (⅓ × ½) = 2 × ⅙ = ⅓
A square has four even sides and the perimeter is equal to the sum of all of the sides.
So we can evaluate the equation for P and then solve for s.
