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gizmo_the_mogwai [7]
3 years ago
7

Please help me with a-c

Mathematics
1 answer:
dem82 [27]3 years ago
5 0

A) The negative rate indicates the glacier is getting smaller ( it is melting).


B) Multiply the size by the rate of change then subtract:

58850 x 0.0004 = 23.54 miles.

58,850 - 23.54 = 58,826.54 square miles.


C) A decade is 10 years.

Multiply the rate of change by 10: 0.0004 * 10 = 0.004

(1 - 0.004)^d or (0.996)^d, where d is the number of decades.

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A jogger runs 140 m due west, then changes direction for the second leg of her run. At the end of the run, she is 374 m away fro
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Answer:

The length of her second displacement = 247.12 m.

The direction of her second displacement = 31.24° from west.

Step-by-step explanation:

As per the question,

From the figure as drawn below,

Let the starting point be O. After running 140 m due west, she reached at point A.

∴ OA = 140 m

And At the end of the run, she is 374 m away from the starting point at an angle of 20° north of west.

∴ OP = 374 m

We have to find the distance AP = x.

By using the cosine rule in triangle OAP

cos \theta = \frac{OA^{2}+OP^{2}-AP^{2}}{2\times OA\times OP}

After putting the given value, we get

cos 20= \frac{140^{2}+374^{2}-x^{2}}{2\times 140\times 374}

x^{2}=140^{2}+374^{2} - 2\times 140\times 374\times cos 20

  ∴ x = 247.12 m  

Hence,the length of her second displacement = 247.12 m.

Again,

By using the cosine rule in triangle OAP, we get

cos \alpha = \frac{OA^{2}+AP^{2}-OP^{2}}{2\times OA\times AP}

After putting the given value, we get

cos \alpha = \frac{140^{2}+247.12^{2}-374^{2}}{2\times 140\times 247.12}

∴ α = 148.759°

Hence, the  direction of her second displacement = 180° - α = 180° - 148.759 = 31.24° from west.

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