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3 years ago

Please help me with a-c

Mathematics

1 answer:

dem82 [27]3 years ago

5 0

A) The negative rate indicates the glacier is getting smaller ( it is melting).

B) Multiply the size by the rate of change then subtract:

58850 x 0.0004 = 23.54 miles.

58,850 - 23.54 = 58,826.54 square miles.

C) A decade is 10 years.

Multiply the rate of change by 10: 0.0004 * 10 = 0.004

(1 - 0.004)^d or (0.996)^d, where d is the number of decades.

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What is the effect of multiplying both sides of an inequality by a negative number? Explain and give an example.

tester [92]

Answer: You would swap the ineqaulity

Step-by-step explanation:

Multiplying or dividing both sides by a negative number reverses the inequality. This means < changes to >, and vice versa. For example, given that 5 < 8 we can multiply both sides by 6 to obtain 30 < 48 which is still true.

5 0

2 years ago

Solve by using elimtation

Wewaii [24]

Answer:

1. x = 5, y = 13/2

2. x = 15 , y = 24

Step-by-step explanation:

Solve the following system:

{8 y + 6 x = 82 | (equation 1)

{6 y + 9 x = 84 | (equation 2)

Swap equation 1 with equation 2:

{9 x + 6 y = 84 | (equation 1)

{6 x + 8 y = 82 | (equation 2)

Subtract 2/3 × (equation 1) from equation 2:

{9 x + 6 y = 84 | (equation 1)

{0 x + 4 y = 26 | (equation 2)

Divide equation 1 by 3:

{3 x + 2 y = 28 | (equation 1)

{0 x + 4 y = 26 | (equation 2)

Divide equation 2 by 2:

{3 x + 2 y = 28 | (equation 1)

{0 x + 2 y = 13 | (equation 2)

Divide equation 2 by 2:

{3 x + 2 y = 28 | (equation 1)

{0 x + y = 13/2 | (equation 2)

Subtract 2 × (equation 2) from equation 1:

{3 x + 0 y = 15 | (equation 1)

{0 x + y = 13/2 | (equation 2)

Divide equation 1 by 3:

{x + 0 y = 5 | (equation 1)

{0 x + y = 13/2 | (equation 2)

Collect results:

Answer: {x = 5, y = 13/2

_____________________________________

Solve the following system:

{8 y + 3 x = 237 | (equation 1)

{3 y + 5 x = 147 | (equation 2)

Swap equation 1 with equation 2:

{5 x + 3 y = 147 | (equation 1)

{3 x + 8 y = 237 | (equation 2)

Subtract 3/5 × (equation 1) from equation 2:

{5 x + 3 y = 147 | (equation 1)

{0 x + (31 y)/5 = 744/5 | (equation 2)

Multiply equation 2 by 5/31:

{5 x + 3 y = 147 | (equation 1)

{0 x + y = 24 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{5 x + 0 y = 75 | (equation 1)

{0 x + y = 24 | (equation 2)

Divide equation 1 by 5:

{x + 0 y = 15 | (equation 1)

{0 x + y = 24 | (equation 2)

Collect results:

Answer: {x = 15 , y = 24

3 0

1 year ago

If f(x) = 2x – 1 and g(x) = f(x + 1), how does the graph of g compare with the graph of f?

zhenek [66]

Answer:

Step-by-step explanation:

the answer is b because the graph will shift to the left by 1 :D

8 0

2 years ago

The base parking charge at a mall on a Sunday is $2 per hour. Given that a vehicle is parked for 4 hours, only $6 is charged. Wh

igor_vitrenko [27]

The percentage that is saved upon parking for 4 hours is 25%.

Parking for 4 hours should warrant $8, but the new deal deducts $2 from the original rate. $2 ÷ $8 = 0.25 or 25%.

Thank your for posting your question. Please feel free to ask me more.

3 0

2 years ago

A set of numbers is shown below:

scZoUnD [109]

The number 4.2 from the set will make the equation x+2=6.2 true.

7 0

2 years ago

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