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3 years ago

Which expression is not a polynomial? A. 3x + 5 B. 2/5x - 21 C. 5 D. x^-3 + 5x

Mathematics

1 answer:

Anettt [7]3 years ago

7 0

Answer:

C. 5

Step-by-step explanation:

"Polynomial" means consisting of several terms, or more than one term.

In A, we see that there are 2 terms (3x and 5), and so it is a polynomial, specifically a binomial.

In B, we also see 2 terms (2/5x and -21), and so it is also a polynomial, specifically a binomial.

In C, we only see one term (5), and so it is a monomial, or having only one term.

In D, we can see 2 terms (x^-3 and 5x), and so it is also a polynomial, specifically a binomial.

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How do I find the missing side length?

kykrilka [37]

Adjacent side to angle 60º=2/3
opposite side to angle 60º=b
hypotenuse=a

cos 60º= adjacent side / hypotenuse
cos 60º=(2/3) / a
a=(2/3) / cos 60º=(2/3) / (1/2)=4/3

tan 60º= opposite side / adjacent side
tan 60º=b / (2/3)
b=(2/3)*tan 60º=(2/3)* √3=2√3 /3

Answer:
a=4/3
b=2√3 /3

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3 years ago

Read 2 more answers

Solve for y. 12x +2y = 26x -70 a) y= 7x - 35 b) y= 20x -35 c) y= 2x + 72 d) x= 2y +36x -70 I CAN'T TELL IF IM DUMB OR NOT

Zepler [3.9K]

Answer:

Step-by-step explanation:

12x + 2y = 26x - 70

2y = 14x - 70

y = 7x - 35

the answer is A

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3 years ago

Read 2 more answers

According to a research center, 16% of all merchandise sold in a particular country gets returned. A department store in a certa

Mamont248 [21]

Answer:

a) point estimate of the proportion of items returned for the population of sales transactions at the store in the given city

Point estimate = 0.3

b) The 95% confidence interval for the proportion of returns at the store in the given city

( 0.19958,0.40042)

Step-by-step explanation:

Given the Population proportion 'P'= 16% = 0.16

Given data a department store in a certain city sampled 80 items sold in January and found that 24 of the items were returned

The sample proportion $p = \frac{x}{n}$

here x =24 and n = 80

The sample proportion $p = \frac{x}{n} = \frac{24}{80} = 0.3$

a) Point estimate:-

A point estimate of the true proportion P

Point estimate = $p = \frac{x}{n}$

point estimate of the proportion of items returned for the population of sales transactions at the store in the given city

$p = \frac{x}{n} = \frac{24}{80} = 0.3$

b) The 95% confidence interval for the proportion

The 95% confidence interval for the proportion of returns at the store in the given city

$(p - z_{\alpha } \sqrt{\frac{p(1-p)}{n} } , p + z_{\alpha }\sqrt{\frac{p(1-p)}{n} } )$

substitute all values we get ,

$(0.3 - 1.96 \sqrt{\frac{0.3(1-0.3)}{80} } , 0.3 + 1.96\sqrt{\frac{0.3(1-0.3)}{80} } )$

on simplification, we get

(0.3-0.10042 ,0.3+0.10042)

( 0.19958,0.40042)

Conclusion:-

a) point estimate of the proportion of items returned for the population of sales transactions at the store in the given city

Point estimate = 0.3

b) The 95% confidence interval for the proportion of returns at the store in the given city

( 0.19958,0.40042)

5 0

4 years ago

We have two varieties of concrete that we can mix together. One is 5% water and 95% concrete mix, and the other is 20% water and

Orlov [11]

Answers:

20 pounds of the 95% concrete mix
10 pounds of the 80% concrete mix

=================================================

Explanation:

x = amount of the 95% concrete mix

y = amount of the 80% concrete mix

Type A mix has 95% concrete. If we have x pounds of this, then 0.95x pounds is pure concrete. Type B mix has 80% concrete. If there are y pounds of this, then 0.80y pounds is pure concrete.

So far we have 0.95x+0.80y pounds of pure concrete from the two mixes

Divide this over 30 to get (0.95x+0.80y)/30

Setting this equal to 0.90 means we want the final mix to be 90% concrete.

Since we want 30 pounds total, we can say x+y = 30 which solves to y = 30-x. We'll use this later

-------------------------------

(0.95x+0.80y)/30 = 0.90

0.95x+0.80y = 30*0.90 .... multiply both sides by 30

0.95x+0.80y = 27

0.95x+0.80(30-x) = 27 ..... plug in y = 30-x

0.95x+0.80*30-0.80*x = 27

0.95x+24-0.80x = 27

0.15x+24 = 27

0.15x = 27-24 ..... subtracting 24 from both sides

0.15x = 3

x = 3/0.15 ........... dividing both sides by 0.15

x = 20

y = 30-x

y = 30-20

y = 10

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3 years ago

Joe takes part in math competitions. A particular contest consists of 25 multiple-choice questions, and each question has 5 poss

marshall27 [118]

Considering the probabilities of getting each question right, his expected score for the test is 90.8.

<h3>How to find Joe's expected score?</h3>

Joe's expected score is given by the sum of the expected score for each question.

We have that:

He is sure of 12 answers, hence for each he expects 6 points.

He randomly guesses on 9 problems, hence he is expected to have a 1/5 probability of earning 6 on them.

For the other 4 problems, he has a 1/3 probability of earning 6 on them, as he will guess from 3 options as he eliminated 2.

Hence his expected score is given by:

E(X) = 12 x 6 + 9 x 1/5 x 6 + 4 x 1/3 x 6 = 90.8.

More can be learned about the expected score of a distribution at brainly.com/question/13617733

#SPJ1

7 0

2 years ago