If you can tell me what the missing number is.

Mathematics

1 answer:

Orlov [11]2 years ago

5 0

Answer:

Step-by-step explanation:

So, to start answering this, lets recall the formula for a rectangles volume:

This formula is :

V=h*w*l

Lets plug in what we know, and solve for the missing variable.

We know that height(h) is 7.

We know that width(w) is 9.

We know that volume(V) is 378.

We are missing length(l)

So:

378=7*9*l

To find length(l), we must iscolate it.

To do this, we must get rid of the 7 and 9.

So lets start by dividing 378 by 9:

378/9=7*9/9*l

42=7*l

Now lets do the same thing with the 7 to iscolate l:

42/7=7/7*l

6=l

So our missing length(l) is 6.

Answer:

l = 6

Hope this helps!

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To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

$\begin{gathered} ax^2+bx+c=0 \\ \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}$

For the given function:

$f(x)=2x^2-10x-3$ $x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}$ $x=\frac{10\pm\sqrt[]{100+24}}{4}$ $\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\ \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\ \end{gathered}$ $\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\ \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}$ $\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\ \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}$

Then, the zeros of the given quadratic function are: