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nikklg [1K]
3 years ago
9

What is 9-6n-(-5n)-(-8)

Mathematics
2 answers:
djyliett [7]3 years ago
6 0
9-6n-(-5n)-(-8)
=9-6n+5n+8
=17-n
mezya [45]3 years ago
4 0
Rewritten: 9 - 6n + 5n + 8

Grouping like terms: -6n + 5n + 9 + 8

That equals to: -n + 17
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Add:(3x2 - 5x + 6) + (9 - 8x - 4x2)​
finlep [7]

You can see by the image how did I get the answer

3 0
3 years ago
If log2 5 = k, determine an expression for log32 5 in terms of k.
lukranit [14]

Answer:

log_3_2(5)=\frac{1}{5} k

Step-by-step explanation:

Let's start by using change of base property:

log_b(x)=\frac{log_a(x)}{log_a(b)}

So, for log_2(5)

log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)

Now, using change of base for log_3_2(5)

log_3_2(5)=\frac{log(5)}{log(32)}

You can express 32 as:

2^5

Using reduction of power property:

log_z(x^y)=ylog_z(x)

log(32)=log(2^5)=5log(2)

Therefore:

log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)

As you can see the only difference between (1) and (2) is the coefficient \frac{1}{5} :

So:

\frac{log(5)}{log(2)} =k\\

log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k

6 0
3 years ago
The geometic mean of 4 and 21
-Dominant- [34]

Answer:

12.5

Step-by-step explanation:

4+21=25

25/2=12.5

4 0
3 years ago
Find the interest rate r compounded monthly if the principal P = $4,300 reaches the future value F = $4,720 in t = 6 years. Roun
kirza4 [7]

Answer:

  1.55%

Step-by-step explanation:

Fill in the values and solve for the rate using the future value formula.

  FV = P(1 +r/n)^(nt)

  4720 = 4300(1 +r/12)^(12·6)

  (4720/4300)^(1/72) = 1 +r/12

  r = 12(4720/4300)^(1/72) -1) ≈ 0.015542

The annual interest rate is about 1.55%.

4 0
3 years ago
Please someone explain how to solve this piecewise function!!!! Im super confused
Xelga [282]

Answer:

From top to bottom:

0, 1, 2, -8, -8

Step-by-step explanation:

We are given the piecewise function:

g(x) = \left\{        \begin{array}{ll}            0.5x+1 & \text{if } x \leq 2 \\            -8 & \text{if } x > 2        \end{array}    \right.

Row 1:

We want to find g(-2).

Since -2 is less than (or equal to) 2, we will use the first equation. Thus:

g(-2)=0.5(-2)+1=-1+1=0

Row 2:

Likewise, 0 is less than or equal to 2. We will continue to use the first equation:

g(0)=0.5(0)+1=1

Row 3:

2 is not less than 2 but it is equal to 2. So we will continue to use the first equation:

g(2)=0.5(2)+1=1+1=2

Row 4 and 5:

Both 4 and 6 are greater than 2. Thus, we will use the second equation. Therefore:

g(4)=-8\text{ and } g(6)=-8

7 0
3 years ago
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