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3 years ago

A target has 4 rings on it. How many different ways could two arrows be distributed on it.

Mathematics

2 answers:

Alexandra [31]3 years ago

4 0

Answer:

2 ways

Step-by-step explanation:

because 2 divided by 4 is 2,and also it's 2 arrows and if placed on each side there is only 2 one side and 2 other side.Hope you get what I mean!

JulsSmile [24]3 years ago

4 0

2 ways, hope you pass

You might be interested in

An observer (O) spots a bird flying at a 35° angle from a line drawn horizontal to its nest. If the distance from the observer (

romanna [79]

Answer:

The correct option is;

17,202 feet

Step-by-step explanation:

The distance from the observer to the bird is given as 21,000 ft

The angle between the line of flight of the bird to the horizontal line from its nest = 35°

With the triangle BNO = A right triangle, we have;

The distance of the bird from its nest = Adjacent leg of the right triangle

The distance of the observer from the bird = Hypotenuse length

Which by trigonometric relations gives;

$cos(35 ^{\circ} )= \dfrac{Adjacent\ leg \ length}{Hypotenuse \ length} = \dfrac{Distance\ of \ bird \ from \ its \ nest}{21,000}$

21,000×cos(35 degrees) = The distance of the bird from its nest = 17,202.2 feet ≈ 17,202 feet.

6 0

4 years ago

Question 15(Multiple Choice Worth 5 points)

ExtremeBDS [4]

Answer:

1 is the answer you needed

5 0

2 years ago

Write the function for the graph.

masha68 [24]

Answer:

answer is (a)

Step-by-step explanation:

first thing we should find the equation which is f(X)=a*b^x

so the always will be the y intercept no matter what

now time to find b if graph that is shown start from 1 until the end of line which is in the graph so you will find it 8 now divide 8 by 4 so 8/4=2

so final equation will be f(x)=2*(4)

i hope i helped out

3 0

3 years ago

Use mathematical induction to prove the statement is true for all positive integers n. 1^2 + 3^2 + 5^2 + ... + (2n-1)^2 = (n(2n-

Charra [1.4K]

Answer:

The statement is true is for any $n\in \mathbb{N}$ .

Step-by-step explanation:

First, we check the identity for $n = 1$ :

$(2\cdot 1 - 1)^{2} = \frac{2\cdot (2\cdot 1 - 1)\cdot (2\cdot 1 + 1)}{3}$

$1 = \frac{1\cdot 1\cdot 3}{3}$

$1 = 1$

The statement is true for $n = 1$ .

Then, we have to check that identity is true for $n = k+1$ , under the assumption that $n = k$ is true:

$(1^{2}+2^{2}+3^{2}+...+k^{2}) + [2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)}{3} +[2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot [2\cdot (k+1)-1]^{2}}{3} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot (2\cdot k +1)^{2} = (k+1)\cdot (2\cdot k +1)\cdot (2\cdot k +3)$

$(2\cdot k +1)\cdot [k\cdot (2\cdot k -1)+3\cdot (2\cdot k +1)] = (k+1) \cdot (2\cdot k +1)\cdot (2\cdot k +3)$

$k\cdot (2\cdot k - 1)+3\cdot (2\cdot k +1) = (k + 1)\cdot (2\cdot k +3)$

$2\cdot k^{2}+5\cdot k +3 = (k+1)\cdot (2\cdot k + 3)$

$(k+1)\cdot (2\cdot k + 3) = (k+1)\cdot (2\cdot k + 3)$

Therefore, the statement is true for any $n\in \mathbb{N}$ .

4 0

3 years ago

Two cargo ships are sailing a direct course into harbor. Ship A is 22 miles from harbor. Ship Bis sailing into harbor on a cours

s344n2d4d5 [400]

Answer:

The distance of ship B from the Harbor is 32.26 miles

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.

I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the <u>COSINE operator</u> to solve for the length of the course of ship B.

$cos(x) = \frac{adjacent}{hypotenuse}$