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PIT_PIT [208]
2 years ago
8

How do you round 5 1/8 to the nearest whole number

Mathematics
2 answers:
makkiz [27]2 years ago
6 0
The answer is 5 because 1/8 is rounded to a whole number.
lara [203]2 years ago
3 0
When you are rounding always remember this rule

0-4 stay on the floor ( stick with the whole number)
5-9 climb the vine (increase one number)

BUT for fractions you have to make the denominator 100 before you can round

1/8 is equal to 0.5/4
multiply 0.5 times 25 and 4 times 25 so 100 is your denominator
which gives you 12.5/100
since 12.5 isn't 5 to 9 you stay on the floor
when i say 5 to 9 and the denominator is 100 its new value becomes 50-90
So, your answer is 5!
Hope I helped!

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Which do the following options represent the measure of arc RA
ANTONII [103]

Answer:

77.2°

Step-by-step explanation:

Consider the triangle JKR.

∠KJR=108.6 (lies on the same line as ∠RJA, angles on a straight line add up to 180)

All the angles in a triangle add up to 180, so:

∠JKR+∠KJR+∠JRK=180

∠JKR+108.6+32.8=180

∠JKR=38.6=∠RKA

Consider ∠RKA. This angle stands on the same arc as ∠RCA.

Since the angle at centre is twice the angle at circumference, 2(∠RKA) = ∠RCA.

2(∠RKA) = ∠RCA

2(38.6)=∠RCA

∠RCA=77.2°

5 0
2 years ago
Given the function below, what value will result in f(x)=10?<br> f(x)=1/2x+8
nignag [31]
10 = 1/2x + 8
2 = 1/2x
X = 4
5 0
3 years ago
Read 2 more answers
The parking spaces in a city lot were created by painting rows of parallel line segments, then painting a line that cuts through
damaskus [11]

the answer is 65 degrees because the line in the middle is a 180 degree angle and 180-115=65. hope this helps :)

4 0
2 years ago
Read 2 more answers
PLZZZZZZZZ HELLLPPPPP DUEEE TODAY!!!!!!!!!!!!!!!!!
Korvikt [17]

Answer:

12^5

Step-by-step explanation:

36^5=3^5×x^5

36÷3=12

8 0
2 years ago
What is the number of subsets of S= {1, 2, 3…10} that contain five element include 3 or 4 but not both?
Ivenika [448]

Answer:

140

Step-by-step explanation:

To construct a subset of S with said property, we have two choices, include 3 in the subset or include four in the subset. These events are mutually exclusive because 3 and 4 can not both be elements of the subset.

First, let's count the number of subsets that contain the element 3.

Any of such subsets has five elements, but since 3 is already an element, we only have to select four elements to complete it. The four elements must be different from 3 and 4 (3 cannot be selected twice and the condition does not allow to select 4), so there are eight elements to select from. The number of ways of doing this is {}_8C_4=70.

Now, let's count the number of subsets that contain the element 4.

4 is already an element thus we have to select other four elements . The four elements must be different from 3 and 4 (4 cannot be selected twice and the condition does not allow to select 3), so there are eight elements to select from, so this can be done in {}_8C_4=70 ways.

We conclude that there are 70+70=140 required subsets of S.

7 0
3 years ago
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