Answer:
Principal: $6,166.67
Principal: $5,200.00
Explanation:
<u><em>1. $6000 for 50 days at 20% p.a</em></u>
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In 20% pa, pa means "per annum", i.e. "per year".
Assume simple interest:
Interest:
- Interest = Principal × number of days × annual rate / 360
- Interest = $6,000 × 50 × 20% / 360 = $166.67
Principal = principal + interest = $6,000 + $166.67 = $6,166.67
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<u><em>2. $5000 for 5 months at 0.8% per month</em></u>
Assume, again, simple interest.
- interest: 0.80% per month
Interest:
- Interest = Principal × number of months × montly rate
- Interest = $5,000 × 5 × 0.80% = $200.00
Principal = principal + interest = $5,000 + $200.00 = $5,200
You can see that the accrued interests depend on the principal, the interest rate, and the time.
Answer:
8 minutes
Step-by-step explanation:
120÷ 15= 8
yup thats pretty much it
Given the dimensions of locker box are length = 6 feet, width = 4 feet, and height = 10 feet.
Wayne wants to cover the box, so we need to find its total surface area. The box is in the shape of rectangular prism.
We know the formula for total surface area of rectangular prism is given as follows :-

T.S.A. = 2·(6 x 4 + 4 x 10 + 10 x 6) = 2·(24 + 40 + 60) = 2·(124) = 248 feet²
Surface Area = 248 squared feet
To cover the locker with waterproof covering, we needed to find the surface area of the box. As we multiplied two dimensions at a time in the formula, so the units are "squared feet".
Hence, option A is correct i.e. squared feet or ft².
Slope is 4/3, y intercept is 2, equation is y=4/3x +2
The expected length of code for one encoded symbol is

where
is the probability of picking the letter
, and
is the length of code needed to encode
.
is given to us, and we have

so that we expect a contribution of

bits to the code per encoded letter. For a string of length
, we would then expect
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have

so that the variance for the length such a string is

"squared" bits per encoded letter. For a string of length
, we would get
.