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3 years ago

A rectangular prism has a length of 14 cm, width of 2 cm, and height of 3 cm. What is the volume?

Mathematics

2 answers:

Cloud [144]3 years ago

4 0

Answer: 84 cubic cm

Step-by-step explanation: You just do 14 times 2 and the answer times 3 which is 84 cubic cm.

Ivenika [448]3 years ago

4 0

Answer: 84 cm³

Explanation: To find the volume of a rectangular prism or a prism or a prism whose base is a rectangle, we use the following formula.

Volume = length × width × height

Since the rectangular prism has a length of 14 cm, a width of 2 cm, and a height of 3cm, we cna plug this information into the formula to get

(14 cm)(2 cm)(3 cm).

(14)(2) is 28 and (28)(3) is 84 and notice that we have

centimeters × centimeters × centimeters or cm³.

So the volume of the given rectangular prism is 84 cm³.

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The green triangle is a dilation of the red triangle with a scale factor of s=1/3 and the center of dilation is at the point (4,

klasskru [66]

Given:

The scale factor is $s=\dfrac{1}{3}$ and the center of dilation is at the point (4,2).

Red is original figure and green is dilated figure.

To find:

The coordinates of point C' and point A.

Solution:

Rule of dilation: If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

$(x,y)\to (k(x-a)+a,k(y-b)+b)$

According to the given information, the scale factor is $\dfrac{1}{3}$ and the center of dilation is at (4,2).

$(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)$ ...(i)

Let us assume the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

$C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)$

$C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)$

$C(-2,11)\to C'(-2+4,3+2)$

$C(-2,11)\to C'(2,5)$

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

$A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)$

From the given figure it is clear that the image of point A is (8,4).

$A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)$

On comparing both sides, we get

$\dfrac{1}{3}(m-4)+4=8$

$\dfrac{1}{3}(m-4)=8-4$

$(m-4)=3(4)$

$m=12+4$

$m=16$

And,

$\dfrac{1}{3}(n-2)+2=4$

$\dfrac{1}{3}(n-2)=4-2$

$(n-2)=3(2)$

$n=6+2$

$n=8$

Therefore, the coordinates of point A are (16,8).

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2 years ago

Identify the augmented matrix for the system of equations.

lord [1]

Answer:

The augmented matrix for the system of equations is $\left[\begin{array}{cccc}0&2&-3&1\\7&0&5&8\\4&1&-3&6\end{array}\right]$ .

Step-by-step explanation:

This system consists in three equations with three variables ( $x$ , $y$ , $z$ ).The augmented matrix of a system of equations is formed by the coefficients and constants of the system of linear equations. In this case, we conclude that the system of equations has the following matrix:

$\left[\begin{array}{cccc}0&2&-3&1\\7&0&5&8\\4&1&-3&6\end{array}\right]$

The augmented matrix for the system of equations is $\left[\begin{array}{cccc}0&2&-3&1\\7&0&5&8\\4&1&-3&6\end{array}\right]$ .

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2 years ago

Sharon was going through the financial records of her company. The profit earned by the company, p(t), over time t, in years, fo

FromTheMoon [43]

For this case what we must do is find a quadratic function that is already factored.
This is because in the factored quadratic equations, it is easier to observe the zeros of the function.
In this case, the zeros of the function represent the time at which the company did not make any profit.
We have the following equation:
p (t) = 40 (t - 3) (t + 2) (t - 5) (t + 3)
We observed that there was no gain in:
t = 3
t = 5
The other roots are discarded because they are negative
Answer:
a.p (t) = 40 (t - 3) (t + 2) (t - 5) (t + 3)

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2 years ago

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Sauron [17]

Answer:

C 18

Step-by-step explanation:

1080/60 = 18

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Xelga [282]

Answer:

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Step-by-step explanation:

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2 years ago

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