2x^2 - 11 = 87
2x^2 = 87 + 11 = 98
x^2 = 98/2 = 49
x = sqrt (49) = + or - 7
Answer:
- 1 1/14 seconds
- 4 2/7 seconds
Step-by-step explanation:
We are being asked for times, so we can express the rate in terms of seconds per meter.
(15 seconds)/(14 meters) = (15/14) seconds per meter = 1 1/14 seconds/meter
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1) It will take Robot A 1 1/14 seconds to go 1 meter.
2) it will take Robot A 4 2/7 seconds to go 4 meters. (4 times as long)
Answer:
16.852
Step-by-step explanation:
All side lengths are the same in an octagon. What you do is take the diamater and multiply it by 0.383. Diamater is the radius doubled.
9514 1404 393
Answer:
Step-by-step explanation:
A graphing calculator answers these questions easily.
The ball achieves a maximum height of 40 ft, 1 second after it is thrown.
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The equation is usefully put into vertex form, as the vertex is the answer to the questions asked.
h(t) = -16(t^2 -2t) +24
h(t) = -16(t^2 -2t +1) +24 +16 . . . . . . complete the square
h(t) = -16(t -1)^2 +40 . . . . . . . . . vertex form
Compare this to the vertex form:
f(x) = a(x -h)^2 +k . . . . . . vertex (h, k); vertical stretch factor 'a'
We see the vertex of our height equation is ...
(h, k) = (1, 40)
The ball reaches a maximum height of 40 feet at t = 1 second after it is thrown.
Answer:
<u>The acceleration is 0.0012 meters/seconds²</u>
Step-by-step explanation:
1. Let's review the information given to answer the question correctly:
Mass = 250,000 kg
Force = 300 Newtons
2. What is the acceleration?
Based on Newton's Second Law of Motion, let's recall that:
Force = Mass * Acceleration
Acceleration = Force/Mass
Replacing with the real values, we have:
Acceleration = 300/250,0000
Acceleration = 0.0012 meters/seconds² (we can't express acceleration using Newtons/kilograms as the unit).
