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Ksivusya [100]
3 years ago
6

What is wrong with or ambiguous about the phrase "four molecules of NaCl"?

Chemistry
1 answer:
Alex787 [66]3 years ago
5 0

Answer:

the NaCl is not considered a molecula

Explanation:

Sodium atoms, (Na +) and chlorine atoms, (Cl-) form a three-dimensional network. The cations and the anions are joined together by electrostatic attraction which we call ionic bonding

Molecules are atoms bound with chemical bond.

You might be interested in
Which of the following is best described by the term macroscopic?
n200080 [17]

Answer:

A

Explanation:

Since macroscopic means visible to the naked eye without a microscope it would be A. This is because we can see active phase changes in real time without any magnification like water boiling or ice melting.

4 0
3 years ago
If I have 340 mL of a 1.5 M NaBr solution, what will the concentration be if I add 560 mL more water to it?
ipn [44]

Answer:

0.5667 M ≅ 0.57 M.

Explanation:

It is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution.

It can be expressed as:

(MV) before dilution = (MV) after dilution.

M before dilution = 1.5 M, V before dilution = 340 mL.

M after dilution = ??? M, V after dilution = 340 mL + 560 mL = 900 mL.

∴ M after dilution = (MV) before dilution/(V) after dilution = (1.5 M)(340 mL)/(900 mL) = 0.5667 M ≅ 0.57 M.

5 0
2 years ago
What has the same number of valence electrons in the outermost shell?
algol [13]

Answer:

Groups

Explanation:

Elements with the same number of valence electrons are found in the same column(group) of the Periodic Table.

4 0
3 years ago
OP
Yuri [45]

the answer is d hope this helps

8 0
3 years ago
Read 2 more answers
in order to find the molar mass of an unknown compound, a research scientist prepared a solution of 0.930 g of an unknown in 125
PtichkaEL [24]

Answer:

Molar mass→ 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

Explanation:

Let's apply the formula for freezing point depression:

ΔT = Kf . m

ΔT = 74.2°C - 73.4°C → 0.8°C

Difference between the freezing T° of pure solvent and freezing T° of solution

Kf = Cryoscopic constant → 5.5°C/m

So, if we replace in the formula

ΔT = Kf . m → ΔT / Kf = m

0.8°C / 5.5 m/°C = m → 0.0516 mol/kg

These are the moles in 1 kg of solvent so let's find out the moles in our mass of solvent which is 0.125 kg

0.0516 mol/kg . 0.125 kg = 6.45×10⁻³ moles. Now we can determine the molar mass:

Molar mass (mol/kg) → 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

3 0
3 years ago
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