Answer:
<u><em>Volume of NaOH, aka V2 = 6.32 mL to 3 sig. fig.</em></u>
A chemistry student weighs out 0.0941 g of hypochlorous acid (HClo) into a 250. ml. volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.2000 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits mL.
Explanation:
1 mole HClO = 74.44g
0.0941g = 
= 0.00126 moles
Concentration = no. of moles/volume in L
Hence, Concentration of HClO = 0.00126/ 0.250L
= 0.005M.
C1V1 =C2V2
0.005 × 250 mL = 0.2 × V2
<u><em>Volume of NaOH, aka V2 = 6.32 mL to 3 sig. fig.</em></u>
Answer:
a b d
these are part of an ecosystem or can be
It is <u>true</u> that ionic compounds are formed from atoms that have opposite charges.
<h3>What are ionic compounds?</h3>
Ionic compounds are chemical compounds made up of ions held together by electrostatic forces termed ionic bonding.
The ionic compound formed is neutrally charged but consists of positively charged ions called cations and negatively charged ions called anions.
For example, the sodium ions attract chloride ions and the chloride ion attracts sodium ions. The result is the formation of an ionic compound with cation Na+ and anion Cl– ions.
Therefore, it is true that an ionic compound is made up of positive and negative ions.
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Not sure but it might be A or B
The value for this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 KJ/mol is 9.91 mol. in equilibrium
<h3>What is an aqueous reaction in
equilibrium?</h3>
When a chemical reaction happens at the liquid state and the formation of reactant and product is the same then the reaction is known as an aqueous reaction in equilibrium denoted by K.
δG = − R T ln
R = universal gas constant 8.313
δG= 20. 46 kj/mol
T = 298 k or 24.4 in celcius.
substituting the value in the equation.
20. 46 kj/mol = 8.313 × 24.4 in celcius × K
K = 8.313 × 24.4 in celcius / 20. 46 kj/mo
k = 9.91 mol .
Therefore, The value of this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 KJ/mol is 9.91 mol. in equilibrium
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