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likoan [24]
3 years ago
10

Energy of position or stored energy is also called

Chemistry
1 answer:
AlekseyPX3 years ago
6 0

Answer: Potential energy

HOPE THIS HELPS

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why is uranium 235 the most commonly used isotope for nuclear fission in current uses in nuclear power generation?
Pachacha [2.7K]
This is because U-235 decays naturally by a process known as alpha radiation. This means that it releases an alpha particle (two neutrons and two protons connected together).
Another reason that U-235 is ideal for producing nuclear power is that unlike most materials, U-235 can undergo induced fission. When a free neutron collides with a U-235 nucleus, the nucleus will usually capture the neutron and split extremely quickly. The splitting of a single U-235 atom can release roughly 200 MeV (million electron volts).
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3 years ago
Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th
mario62 [17]

<u>Answer:</u> The freezing point of solution is 2.6°C

<u>Explanation:</u>

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

\Delta T_f = \text{Freezing point of pure solution}-\text{Freezing point of solution}

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_f = molal freezing point depression constant = 5.12 K/m  = 5.12 °C/m

m_{solute} = Given mass of solute (anthracene) = 7.99 g

M_{solute} = Molar mass of solute (anthracene) = 178.23  g/mol

W_{solvent} = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC

Hence, the freezing point of solution is 2.6°C

8 0
3 years ago
A chemical bond is a strong attraction between two or more atoms. Can you identify the properties of different types of chemical
kakasveta [241]

Answer:

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2.Ions

3. Covalent

4.Single bond

5. Double bond

6. Polar bond

7.Non polar bond

8. Hydrogen bond

5 0
2 years ago
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The answer is PO4^-3 is non-polar.
8 0
3 years ago
A force of 129,000 N is accelerating a car at 84 m/s/s<br> what’s the mass of the car?
Marianna [84]
M=f/a m=129000N/84m/s/s=1535.714286kg/m/s/s
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2 years ago
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