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3 years ago

10

Energy of position or stored energy is also called

1 answer:

AlekseyPX3 years ago

6 0

Answer: Potential energy

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Compute the following and give your answer on scientific notation

Nata [24]

Answer:

6*10^-3

Hope it helps

Procedure in the attached file

4 0

2 years ago

Based on Chromium's position on the periodic table, which statement describes the element

natali 33 [55]

Answer:

C. chromium is a metal that is less reactive than sodium.

Explanation:

Hello.

Given the options:

A. chromium is a nonmetal and therefore a good conductor of heat and electricity .

B. chromium is a metal that is more reactive than potassium .

C. chromium is a metal that is less reactive than sodium .

D. chromium is a noble gas that is not reactive.

In this case, since chromium is in period 4 group VIB we infer it is a transition metal which slightly reacts with acids and poorly reacts with oxygen and other oxidizing substances. Thus, in comparison with both sodium and potassium which are highly reactive even with water as they get on fire, we can say that it is less reactive than both potassium and sodium, therefore, answer is: C. chromium is a metal that is less reactive than sodium.

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7 0

3 years ago

How many milliliters of a 0.215 molar solution are required to contain 0.0867 mol of NaBr

JulsSmile [24]

Answer: 403ml

Explanation:

$M=\frac{mol}{L}$

Solve for L;

$L=\frac{mol}{M}\\L=\frac{0.0867mol}{0.215M}\\ L=0.403L$

Convert to mililiters

$0.403L(\frac{1000ml}{1L})=403ml$

3 0

2 years ago

Carbonated drinks in cans have a small amount of space above the liquid level inside the can known as the “headspace.” What woul

andrey2020 [161]

The temperature will stay constant.

3 0

3 years ago

Read 2 more answers

10.0 g Cu, C Cu = 0.385 J/g°C 10.0 g Al, C Al = 0.903 J/g°C 10.0 g ethanol, Methanol = 2.42 J/g°C 10.0 g H2O, CH2O = 4.18 J/g°C

Mazyrski [523]

Answer:

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

Explanation:

$Q=mc\Delte T$

Q = Energy gained or lost by the substance

m = mass of the substance

c = specific heat of the substance

ΔT = change in temperature

1) 10.0 g of copper

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the copper = c = 0.385 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.385J/g^oC}=25.97^oC$

2) 10.0 g of aluminium

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the aluminium= c = 0.903 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.903 J/g^oC}=11.07^oC$

3) 10.0 g of ethanol

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the ethanol= c = 2.42 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 2.42 J/g^oC}=4.13 ^oC$

4) 10.0 g of water

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the water = c = 4.18J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 4.18 J/g^oC}=2.39 ^oC$

5) 10.0 g of lead

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the lead= c = 0.128 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.128 J/g^oC}=78.125^oC$

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

3 0

3 years ago