Answer: B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
Step-by-step explanation:
Here are the options:
A There are more boys at Mark's school than at Leslie's school because the ratio 11 to 12 is greater than the ratio 41 to 48.
B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
C. There are more boys at Leslie's school than at Mark's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
At leslie's school the ratio of boys and girls is 11 to 12. This implies that the fraction of boys in the school to total students will be:
= 11/(11 + 12) = 11/23 = 0.4783
At Marks school the ratio of boys to girls is 41 to 48. Thus implies that the fraction of boys in the school to total students will be:
= 41 / (41 + 48) = 41/85= 0.4824
Based on the calculation, we can deduce that there are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
Answer:
Like 3/5? Or something?
Step-by-step explanation:
Jk that's 63%
Good luck!
(x, y) = ( 
, 
)
given the 2 equations
5x - 3y - 10 = 0 → (1)
x + y - 7 = 0 → (2)
rearrange (2) to obtain y in terms of x
y = 7 - x → (3)
Substitute y = 7 - x into (1)
5x - 3(7 - x) - 10 = 0
5x - 21 + 3x - 10 = 0
8x - 31 = 0 ( add 31 to both sides )
8x = 31 ( divide both sides by 8 )
x =
Substitute this value into (3) for y
y = 7 - x = 
- =
The Answer For This Is 5^3<span>√10 - 1/2</span>
