Answer:
(x + 1 s 1) n (x + 12 1)
(x +1<1) n (x + 1 > 1)
Step-by-step explanation:
Just simplify each the statements.
Then compare and and see if the statements are contradictory and therefore FALSE, if so, then there is no solution.
(x + 1<-1) n (x + 1< 1)
(x <-2) n (x < 0) which is true, so there is a solution.
(x + 1 s 1) n (x + 12 1)
this doesn't make sense so there is no solution.
(x +1<1) n (x + 1 > 1)
(x < 0) n (x > 0)
This is not possible, the statements are contradictory and therefore FALSE, so there is no solution.
Answer:
Triangle 1: x = 80 degrees, acute
Triangle 2: x = 10 degrees, right
Step-by-step explanation:
Triangle 1:
By the Sum of Interior Angles Theorem, all the angles inside the triangle adds up to 180 degrees. So, set up this equation:
Solve for x:
So, x = 80 degrees
Because all the angles are less than 90 degrees, this is an acute triangle.
Triangle 2:
By the Sum of Interior Angles Theorem, all the angles inside the triangle adds up to 180 degrees. So, set up this equation (with the right angle given):
Solve for x:
So, x = 10 degrees
Because there is an angle measuring 90 degrees, this is a right triangle.
Answer:
3.036, 3.36, 3.3661 , 3.5
Step-by-step explanation:
Look at the first 2 numbers
3.3661, 3.5, 3.36, 3.036
We can order them as 3.0 , 3.3 , 3.3 . 3.5
So 3.036 is first one
Now we have 2 of the 3.3's
One is 3.3661 and the other one is 3.3600
Because if you add a number to the end it will always be a zero and it wont change the answer
So 3.36 is second and 3.3661 is third one
3.5 is bigger than 3.3
So 3.5 is last
6 / 1/3 = 18
Hope I helped!
~ Zoe
The correct answer is: [B]: "40 yd² " .
_____________________________________________________
First, find the area of the triangle:
The formula of the area of a triangle, "A":
A = (1/2) * b * h ;
in which: " A = area (in units 'squared') ; in our case, " yd² " ;
" b = base length" = 6 yd.
" h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
___________________________________________________
→ A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ;
= " 24 yd² " .
___________________________________________________
Now, find the area, "A", of the square:
The formula for the area, "A" of a square:
A = s² ;
in which: "A = area (in "units squared") ; in our case, " yd² " ;
"s = side length (since a 'square' has all FOUR (4) equal side lengths);
A = s² = (4 yd)² = 4² * yd² = "16 yd² "
_________________________________________________
Now, we add the areas of BOTH the triangle AND the square:
_________________________________________________
→ " 24 yd² + 16 yd² " ;
to get: " 40 yd² " ; which is: Answer choice: [B]: " 40 yd² " .
_________________________________________________
