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ELEN [110]
4 years ago
7

Find the image of (0,0) after two reflections, first across x= -2 and then across the y- axis

Mathematics
1 answer:
kenny6666 [7]4 years ago
7 0

Answer: -2,-2

Step-by-step explanation:

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Help me pleaseeeeeee
Pepsi [2]

so I don't know but just use the internet

5 0
3 years ago
Describe a sequence of transformations that can be performed to polygon ABCDE to prove that it is similar to polygon FGHIJ
maxonik [38]

Answer:

answer below

Step-by-step explanation:

ABCDE go through dilation over center (6 , -2) with factor of 1/2 to FGHIJ

AB // FG slope: -2 , √20:√5 = 2: 1

BC // GH // X axis 8:4 = 2:1

CD // HI, slope= 1 , √8:√2 = 2:1

DE // IJ // x axis, 4:2 = 2:1

EA // JF // y axis, 2:1

8 0
3 years ago
Tina is planning to fence in an area for her dog. She wants to create a rectangular area of 1,600 square feet for her pet and ca
castortr0y [4]

The dimensions of the rectangular area of Tina's fence is 40 ft by 40 ft

<h3 />

<h3>Area of a rectangle:</h3>
  • area = lw

where

l = length

w = width

She wants to create a rectangular area of 1,600 square feet for her pet . Therefore,

  • area = 1600 ft²

lw = 1600

Therefore,

perimeter = 160 ft

Then,

perimeter of rectangle = 2(l + w)

160 = 2(l + w)

l + w = 80

Let's combine the equations

lw = 1600

l + w = 80

l = 80 - w

Therefore,

w(80 - w) = 1600

80w - w² = 1600

Therefore,

w² - 80w + 1600 = 0

w² - 40w - 40w + 1600 = 0

w(w - 40) - 40(w - 40) = 0

(w - 40)(w - 40) = 0

w = 40 or 40

Therefore, the dimensions can be calculated as follows:

lw = 1600

40l = 1600

l = 1600 / 40

l = 40 ft

Therefore, the dimensions are 40ft by 40 ft

learn more on algebraic model here: brainly.com/question/4151078

4 0
3 years ago
Find the mass. Volume=2.3cm cubed<br> Density=4.1g/cm cubed
Yakvenalex [24]
Density = mass / volume 
So if we know the density and volume, make an algebraic equation of this. 
4.1 = m ÷ 2.3 
Multiply each side by 2.3. 
9.43 = m 
The mass is 9.43 grams, hope this helps!
3 0
3 years ago
M
Misha Larkins [42]

Answer:

The length of the box is (x + 1)

The height of the box is (x + 1)

Step-by-step explanation:

The given function representing the volume of the box is presented as follows;

V = x³ + 6·x² + 9·x + 4

The function representing the width of the box, W = x + 4

Therefore, we have;

(x³ + 6·x² + 9·x + 4)/(x + 4) = x² + 2·x + 1

x³ + 4·x²

    {}  2·x² + 9·x + 4

    {}  2·x² + 8·x

    {}               x + 4

Therefore, we have;

(x³ + 6·x² + 9·x + 4) = (x + 4) × (x² + 2·x + 1) = (x + 4) × (x + 1) × (x + 1)

(x³ + 6·x² + 9·x + 4) = (x + 4) × (x + 1) × (x + 1)

The width of the box = (x + 4)

The length of the box = (x + 1)

The height of the box = (x + 1).

6 0
3 years ago
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