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vekshin1
3 years ago
7

Find the cost of 20 grams of lead at 60$ per kilogram

Mathematics
1 answer:
ASHA 777 [7]3 years ago
6 0

Answer:

$1.20

Step-by-step explanation:

Ratio:

Grams : Kilograms

1 : .001

Multiply both sides by 20 to convert grams to kilograms:

Grams : Kilograms

1 : .001

x20 x20

20 : .02

This means that 20 grams of lead = .02 kilograms of lead

Price:

Cost : Kilogram

$60 : 1

Multiply both sides by .02 to find the price of the lead:

Cost : Kilogram

$60 : 1

x.02  x.02

$1.20 : .02

Therefore, .02 kg of lead costs $1.20.

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Find the sum of the first 10 terms of the following series, to the nearest integer.
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Answer:

Step-by-step explanation:

you can see this is a geometric progression which a ratio of {2\over{5}}. the sum of the firs n term is:

S=a_1\frac{(1-r^n)}{(1-r)}=175\frac{1-(\frac{2}{5})^{10}}{1-\frac{2}{5}}=291.6360832

the nearest integer would be:

292

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3 years ago
The height of a small rock falling from the top of a 124-ft-tall building with an initial downward velocity of –30 ft/sec is mod
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Answer:

Option 3.

Step-by-step explanation:

The given function is

h(t)=-16t^2-30t+124

where, h(t) is the height of a small rock falling from the top of a 124-ft-tall building and t is the time in seconds.

It is a downward parabola.

Equate the function equal to 0, to find the time at which the rock touch the ground.

-16t^2-30t+124=0

If ax^2+bx+c=0, the according to the quadratic formula

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Using quadratic formula, we get

t=\dfrac{-(-30)\pm \sqrt{(-30)^2-4(124)(-16)}}{2(-16)}

t=\dfrac{30+\sqrt{(-30)^2-4(124)(-16)}}{2(-16)},\dfrac{30-\sqrt{(-30)^2-4(124)(-16)}}{2(-16)}

t=-3.875, 2

Time cannot be negative. So, the rock remain in the air in the interval 0 < t < 2.

Therefore, the correct option is 3.

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3 years ago
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Writing numbers in Expanded Form
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Break the number apart into hundreds, tens, ones, etc. and add the quantities together. Here is an example:

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Step-by-step explanation:

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