Answer:
The concentration of the most dilute solution is 0.016M.
Explanation:
First, a solution is prepared and then it undergoes two subsequent dilutions. Let us calculate initial concentration:
![[Na_{2}SO_{4}]=\frac{moles(Na_{2}SO_{4})}{liters(solution)} =\frac{mass((Na_{2}SO_{4}))}{molarmass(moles(Na_{2}SO_{4}) \times 0.100L)} =\frac{2.5316g}{142g/mol\times 0.100L } =0.178M](https://tex.z-dn.net/?f=%5BNa_%7B2%7DSO_%7B4%7D%5D%3D%5Cfrac%7Bmoles%28Na_%7B2%7DSO_%7B4%7D%29%7D%7Bliters%28solution%29%7D%20%3D%5Cfrac%7Bmass%28%28Na_%7B2%7DSO_%7B4%7D%29%29%7D%7Bmolarmass%28moles%28Na_%7B2%7DSO_%7B4%7D%29%20%5Ctimes%200.100L%29%7D%20%3D%5Cfrac%7B2.5316g%7D%7B142g%2Fmol%5Ctimes%200.100L%20%7D%20%3D0.178M)
<u>First dilution</u>
We can use the dilution rule:
C₁ x V₁ = C₂ x V₂
where
Ci are the concentrations
Vi are the volumes
1 and 2 refer to initial and final state, respectively.
In the first dilution,
C₁ = 0.178 M
V₁ = 15 mL
C₂ = unknown
V₂ = 50 mL
Then,
<u>Second dilution</u>
C₁ = 0.053 M
V₁ = 15 mL
C₂ = unknown
V₂ = 50 mL
Then,
Ammonia gas will have a mass of 3.17grams.
HOW TO CALCULATE MASS:
- The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass.
- However, to calculate the number of moles present in the ammonia gas given in this question, we use the formula as follows:
where;
- P = pressure (atm)
- V = volume (L)
- n = number of moles (mol)
- R = gas law constant
- T = temperature
n = PV ÷ RT
n = (1.2 × 3.7) ÷ (0.0821 × 290)
n = 4.44 ÷ 23.81
n = 0.186mol
- Mass of ammonia gas = 3.17g
- Therefore, the mass of ammonia gas is 3.17grams.
Learn more at: brainly.com/question/21085277?referrer=searchResults
Answer:
I think it's lead (pb). Hope this helps.
"Caesium" is the strongest reducing agent in Periodic table.
Hope this helps!
Answer:
A
Explanation:
i did it before and got it right
