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natima [27]
3 years ago
13

Identify the spectator ions in the following complete ionic equation.

Chemistry
1 answer:
krok68 [10]3 years ago
5 0
<span>Ba2+(aq)+2I−(aq)+2Na+(aq)+SO2−4(aq)→BaSO4(s)+2I−(aq)+2Na+(aq)

The spectator ions are:    </span><span>Na</span>⁺,  I⁻.

They appear on both sides of the reaction, hence did not take part in the reaction.
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HELP! <br> A train travels 102 miles in 2 5/6 hours. What is its average speed in miles per hour?
aniked [119]

Answer:

36miles/hour

Explanation:

speed =distance÷time taken

102miles/2 5/6

102÷17/6

102×6/17

=36miles per hour

5 0
3 years ago
Use the atom builder interactive to identify each nucleus. Two protons represented as purple spheres and one neutron represented
aleksandr82 [10.1K]

Answer:

\frac{3}{2}He

\frac{6}{2} He

\frac{7}{4}Be

\frac{3}{1} H

\frac{6}{4}Be

\frac{7}{3} Li

Explanation:

In the first nucleus we are told that there are two protons and one neutron. Let us remember that the mass number = number of protons + number of neutrons.

This implies that, for the first specie the mass number is 3, for the second specie the mass number is 6 and the third specie has a mass number of 7 and so on. The mass number is indicated as a superscript.

The atomic number is the number of protons in the nucleus of the atom and helps us to identify the atom. It is always written as a subscript as shown.

5 0
3 years ago
What is the molarity of a solution
Dafna1 [17]

Answer:

multiple that number

Explanation:

it the right way to do it

8 0
3 years ago
To measure the volume of the blood system of an animal, the following experiment was done. A 1.0-mL sample of an aqueous solutio
Artyom0805 [142]

Answer:199mL

Explanation:

Let V ml be the volume of blood in animal.

When 1.0 ml sample is added, total volume becomes V+1.0ml. Its activity is 1000 dpm.

After equilibrium, 2.0 ml of the sample had activity of 10 dpm.

Hence, after equilibrium, the activity of V+1.0 ml of blood sample will be 10/2 (V+1.0ml)=1000dpm

Hence, V=199ml.

4 0
3 years ago
In a laboratory experiment, after purification, 4.567 g of nickel metal was obtained by a student. The student then calculated,
DaniilM [7]

Answer:

The yield of the purification is 79.7%

Explanation:

Hi there!

5.731 g nickel metal could be produced by the student if the yield of the purification would be 100%. Instead, 4.567 g was obtained. Then, the yield of the purification can be calculated as follows:

4.567 g Ni · (100% / 5.731 g) = 79.7%

The yield of the purification is 79.7%

Have a nice day!

5 0
4 years ago
Read 2 more answers
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