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We know that the perimeter of a rectangle is 2(width)+2(length). We can multiply the length by 2 to find out how much remaining fencing we have, then divide that number by 2 to find the width.
15.5*2=31
170.5-31=139.5
139.5/2=69.75
A possible width is 69.75 feet.
Hello!
To find the y-values of the given ordered pairs, substitute the x-values into the equation, y = log₂ x.
y = log₂ 1/2, y = -1
y = log₂ 1, y = 0
y = log₂ 2, y = 1
y = log₂ 4, y = 2
y = log₂ 8, y = 3
y = log₂ 16, y = 4
Therefore, the ordered pairs of y = log₂ x is: {(1/2, -1), (1, 0), (2, 1), (4, 2), (8, 3), (16, 4)}.
Answer:
Area= 70x^3y^2
Perimeter = 20x^2 + 14 xy^2
Step-by-step explanation:
Area is just multiplying the length and width, I multiplied the constants first which gets us 70 then multiplied the variables, they combine however only the x's can be multiplied to each other which results in 70x^3y^2 . The perimeter you just multiply the length by two and the width by two, they are separate because the variables when added to each other do not combine.
-2+5=3
And is a word used for addition. For example 20 and 6 is 26.
