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3 years ago

Solve for x. (x+8)^2=x^2+4x+16

2 answers:

5 0

(x+8)^2=x^2+4x+16 Simplify both sides of the equation. x^2+16x+64=x^2+4x+16 Subtract x^2 from both sides. x^2+16x+64−x^2=x^2+4x+16−x^2 16x+64=4x+16 Subtract 4x from both sides. 16x+64−4x=4x+16−4x 12x+64=16 Subtract 64 from both sides. 12x+64−64=16−64 12x=−48 Divide both sides by 12.‌ 12x/12‌=‌−48/12‌ x=−4 Answer:x=−4

wariber [46]3 years ago

3 0

Expanding the left side:-

x^2 + 16x + 64 = x^2 + 4x + 16
x^2 - x^2 +16x - 4x + 64 - 16 = 0
12x + 48 = 0
12 x = -48
x = -4

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