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3 years ago

How many integers between 10 and 500 begin and end in 3?

Mathematics

1 answer:

hodyreva [135]3 years ago

5 0

If from 0 - 10 there is 1 number ending in 3 (3) we'll aplly the same logic to 500.

Between 0-10 there is 3. Between 10 - 20 there is 13. Between 20-30 there is 23. Between 30-40 there is 33, etc.

If we divide 500 into 10 we get 50:

500 / 10 = 50

That means there are 50 groups of 10 in the number 500. If we know that every 10 numbers has 1 ending in 3, we multiply 1 by 50:

1 x 50 = 50

So, our conclusion is, that there are 50 numbers ending in 3 between 10 and 500.

Hope it helped,

BioTeacher101

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As a sales person Jonathan is paid 50 per week +3% of the total Amount he sells. This week he wants to earn at least 100. Write

steposvetlana [31]

Answer:

The Inequality with integer coefficient for the total sales is $5000+3x\geq 10000$

Hence Jonathan should make total sales of at least 1667 to earn at least 100.

Step-by-step explanation:

Given:

Amount paid per week = 50

Addition amount = 3% of Total sales.

Let the Total sales be 'x'.

∴ Additional amount = $\frac{3}{100}x$

Amount he wants to earn this week $\geq$ 100

We need to write the inequality with integer coefficient for the total sales and also to find the total sales.

Solution:

We cans say that;

Amount paid per week plus Additional amount should be greater than or equal to Amount he wants to earn this week.

framing in equation form we get;

$50+\frac{3}{100}x\geq 100$

Now we will make the denominator common using LCM we get;

$\frac{50\times100}{100}+\frac{3}{100}x\geq 100$

$\frac{5000}{100}+\frac{3}{100}x\geq 100$

$\frac{5000+3x}{100}\geq 100$

Multiplying both side by 100 we get;

$100 \times\frac{5000+3x}{100}\geq 100\times 100\\\\5000+3x\geq 10000$

Hence The Inequality with integer coefficient for the total sales is $5000+3x\geq 10000$

On solving the above equation we get;

Subtracting both side by 5000 we get;

$5000+3x-5000\geq 10000-5000\\\\3x\geq 5000$

Dividing both side by 3 we get;

$\frac{3x}{3}\geq \frac{5000}{3}\\\\x\geq 1666.67$

Hence Jonathan should make total sales of at least 1667 to earn at least 100.

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Use ZPP
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